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Commit ef8f39a

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Merge pull request #80 from arpitjain22june/patch-12
Create SumTriplet.java
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Take as input N, the size of array. Take N more inputs and store that in an array. Take as input "target", a number. Write a function which prints all triplets of numbers which sum to target.
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Input Format
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First line contains input N.
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Next line contains N space separated integers denoting the elements of the array.
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The third line contains a single integer T denoting the target element.
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Constraints
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Length of Array should be between 1 and 1000.
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Output Format
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Print all the triplet present in the array in a new line each. The triplets must be printed as A, B and C where A,B and C are the elements of the triplet ( A<=B<=C) and all triplets must be printed in sorted order. Print only unique triplets.
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Sample Input
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9
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5 7 9 1 2 4 6 8 3
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10
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Sample Output
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1, 2 and 7
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1, 3 and 6
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1, 4 and 5
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2, 3 and 5
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Explanation
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Array = {5, 7, 9, 1, 2, 4, 6 ,8 ,3}. Target number = 10. Find any three number in the given array which sum to target number.
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import java.util.Arrays;
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import java.util.Scanner;
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public class SumTriplet {
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//find triplet with sum =x
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public static void main(String[] args) {
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Scanner sc = new Scanner(System.in);
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int n = 0;
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if (sc.hasNext()) {
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n = sc.nextInt();
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}
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int[] a = new int[n];
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for (int i = 0; i < n; i++) {
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a[i] = sc.nextInt();
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}
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Arrays.sort(a);
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int x = sc.nextInt();
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for (int i = 0; i < n - 2; i++) {//loop for a fix number and rest like sum pair
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int l = i + 1;
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int h = n - 1;
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while (l < h) {
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int s = a[i] + a[l] + a[h];
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if (s == x) {
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System.out.println(a[i] + ", " + a[l] + " and " + a[h]);
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l++;
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h--;
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} else if (s > x) {
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h--;
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} else {
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l++;
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}
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}
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}
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}
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}

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