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Commit 82defae

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added: three sum
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# three sum | leetcode 15 | https://leetcode.com/problems/3sum/
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# - sorted; nested loop; outer loop for first element
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# - inner loop for two sum on rest of list
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# - avoid duplicates by shifting window till last occurrence
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class Solution:
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def threeSum(self, nums: list[int]) -> list[list[int]]:
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nums.sort()
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N = len(nums)
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triplets = []
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for i in range(N):
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if i > 0 and nums[i] == nums[i - 1]:
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continue
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ptrL = i + 1
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ptrR = N - 1
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while ptrL < ptrR:
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s = nums[i] + nums[ptrL] + nums[ptrR]
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if s > 0:
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ptrR -= 1
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elif s < 0:
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ptrL += 1
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else:
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triplets.append([nums[i], nums[ptrL], nums[ptrR]])
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ptrL += 1
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while nums[ptrL] == nums[ptrL - 1] and ptrL < ptrR:
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ptrL += 1
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return triplets

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