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Commit 06565fb

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added: non-overlapping intervals
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# non-overlapping intervals | leetcode 435 | https://leetcode.com/problems/non-overlapping-intervals
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# sort by starting times; keep track of latest ending time; always keep interval with min end time
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class Solution:
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def eraseOverlapIntervals(self, intervals: list[list[int]]) -> int:
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min_intervals_to_remove = 0
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intervals.sort(key = lambda x: x[0])
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latest_end = intervals[0][1]
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for i in range(1, len(intervals)):
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if intervals[i][0] < latest_end:
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min_intervals_to_remove += 1
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latest_end = min(intervals[i][1], latest_end)
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else:
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latest_end = intervals[i][1]
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return min_intervals_to_remove

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