Commit 1c696ff

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Merge pull request avinashkranjan#2855 from smty2018/pwd-checker

Common Password Checker GUI

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	`1`	`+Password Checker GUI :`
	`2`	`+`
	`3`	`+GUI application that allows you to check if a given password is common or unique. Check if a password is common or unique based on a list of common passwords.Displays a message box with the results of the password check.`
	`4`	`+`
	`5`	`+Requirements:`
	`6`	`+pip install tkinter`

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	`1`	`+import tkinter as tk`
	`2`	`+from tkinter import messagebox`
	`3`	`+`
	`4`	`+def check_password(password):`
	`5`	`+ with open("pwd.txt", "r") as file:`
	`6`	`+ common_passwords = file.read().splitlines()`
	`7`	`+`
	`8`	`+ for i, common_pwd in enumerate(common_passwords, start=1):`
	`9`	`+ if password == common_pwd:`
	`10`	`+ messagebox.showinfo("Password Check", f"{password}: not unique (#{i})")`
	`11`	`+ return`
	`12`	`+`
	`13`	`+ messagebox.showinfo("Password Check", f"{password}: unique")`
	`14`	`+`
	`15`	`+def main():`
	`16`	`+ app = tk.Tk()`
	`17`	`+ app.title("Password Checker")`
	`18`	`+ app.configure(bg="black")`
	`19`	`+`
	`20`	`+ label = tk.Label(app, text="Enter Password:", fg="white", bg="black")`
	`21`	`+ label.pack()`
	`22`	`+`
	`23`	`+ password_entry = tk.Entry(app, show="*")`
	`24`	`+ password_entry.pack()`
	`25`	`+`
	`26`	`+ check_button = tk.Button(app, text="Check", command=lambda: check_password(password_entry.get()))`
	`27`	`+ check_button.pack()`
	`28`	`+`
	`29`	`+ app.mainloop()`
	`30`	`+`
	`31`	`+if __name__ == "__main__":`
	`32`	`+ main()`

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