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`@@ -1557,3 +1557,37 @@ ON employee.team_id = team.team_id;`
`1557`	`1557`	`---`
`1558`	`1558`
`1559`	`1559`	`[⬆ Back to Top](#sql-coding-challenges-for-beginners)`
	`1560`	`+`
	`1561`	`+## 46. Monsters using CASE`
	`1562`	`+`
	`1563`	+You have access to two tables `top_half` and `bottom_half`. Write a SQL query to return the results as outlined below. The IDs on the tables match to make a full monster. For the `species`, if the monster has more heads than arms or more tails than legs, it is a `BEAST`, else it is a `WEIRDO`. Order your results by `species`.
	`1564`	`+`
	`1565`	+```
	`1566`	`+top_half bottom_half output`
	`1567`	`+-------- ----------- ------`
	`1568`	`+id id id`
	`1569`	`+heads legs heads`
	`1570`	`+arms tails legs`
	`1571`	`+ arms`
	`1572`	`+ tails`
	`1573`	`+ species`
	`1574`	+```
	`1575`	`+`
	`1576`	`+<details><summary>Solution</summary>`
	`1577`	`+`
	`1578`	+```sql
	`1579`	`+SELECT T.id, heads, legs, arms, tails,`
	`1580`	`+CASE`
	`1581`	`+ WHEN heads > arms OR tails > legs THEN 'BEAST'`
	`1582`	`+ ELSE 'WEIRDO'`
	`1583`	`+END AS species`
	`1584`	`+FROM top_half T JOIN bottom_half B`
	`1585`	`+ON T.id = B.id`
	`1586`	`+ORDER BY species;`
	`1587`	+```
	`1588`	`+`
	`1589`	`+</details>`
	`1590`	`+`
	`1591`	`+---`
	`1592`	`+`
	`1593`	`+[⬆ Back to Top](#sql-coding-challenges-for-beginners)`

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