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Commit cc7cdca

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updating sql queries

Mysql branch brings updates

2 parents 320fb1f + c65e2a2 commit cc7cdcaCopy full SHA for cc7cdca

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+51

-37

lines changed

+51

-37

lines changed

Lines changed: 7 additions & 13 deletions

Original file line number	Diff line number	Diff line change
`@@ -1,17 +1,11 @@`
	`1`	`+/*`
`1`	`2`	`# Time: O(n)`
`2`	`3`	`# Space: O(n)`
	`4`	`+*/`
`3`	`5`
`4`		`-SELECT DISTINCT(Num) AS ConsecutiveNums`
`5`		`-FROM (`
`6`		`- SELECT`
`7`		`- Num,`
`8`		`- @counter := IF(@prev = Num, @counter + 1, 1) AS how_many_cnt_in_a_row,`
`9`		`- @prev := Num`
`10`		`- FROM Logs y, (SELECT @counter:=1, @prev:=NULL) vars`
`11`		`-) sq`
`12`		`-WHERE how_many_cnt_in_a_row >= 3`
`13`		`-`
`14`		`-SELECT DISTINCT l1.Num as ConsecutiveNums`
`15`		`-FROM Logs l1, Logs l2, Logs l3`
`16`		`-WHERE l1.Id + 1 = l2.Id AND l2.Id + 1 = l3.Id AND l1.Num = l2.Num AND l2.Num = l3.Num`
	`6`	`+/ this is a ms sql script /`
`17`	`7`
	`8`	`+/* Write your T-SQL query statement below */`
	`9`	`+SELECT DISTINCT l1.num AS ConsecutiveNums`
	`10`	`+FROM Logs l1, Logs l2, Logs l3`
	`11`	`+WHERE l1.id = l2.id - 1 AND l2.id = l3.id - 1 AND l1.num = l2.num AND l2.num = l3.num;`

Lines changed: 6 additions & 1 deletion

Original file line number	Diff line number	Diff line change
`@@ -1,5 +1,10 @@`
`1`	`1`	`# Time: O(n^2)`
`2`	`2`	`# Space: O(n)`
`3`	`3`
`4`		`-SELECT Email FROM Person GROUP BY Email HAVING COUNT(*) > 1`
	`4`	`+/ # Write your MySQL query statement below /`
	`5`	`+`
	`6`	`+SELECT Email`
	`7`	`+FROM Person`
	`8`	`+GROUP BY Email`
	`9`	`+HAVING COUNT(*) > 1`
`5`	`10`

Lines changed: 9 additions & 9 deletions

Original file line number	Diff line number	Diff line change
`@@ -1,13 +1,13 @@`
`1`	`1`	`# Time: O(n^2)`
`2`	`2`	`# Space: O(1)`
`3`	`3`
`4`		`-SELECT e.Name AS Employee FROM Employee e LEFT JOIN Employee b`
`5`		`- ON e.ManagerId=b.Id`
`6`		`-WHEREe.Salary>b.Salary`
`7`		`-`
`8`		`-SELECT Name AS Employee`
`9`		`-FROM Employee e`
`10`		`-WHEREe.ManagerIdIS NOT NULLANDe.Salary> (SELECT Salary`
`11`		`-FROM Employee`
`12`		`-WHERE e.ManagerId= Id)`
	`4`	`+SELECT e.Name AS Employee FROM Employee e LEFT JOIN Employee b`
	`5`	`+ ON e.ManagerId=b.IdWHEREe.Salary>b.Salary`
	`6`	`+`
	`7`	`+/ # Write your MySQL query statement below /`
	`8`	`+/ solution two /`
	`9`	`+`
	`10`	`+SELECTe.nameAS employee`
	`11`	`+FROM employee AS e JOIN employee AS e1 ONe.managerid=e1.id`
	`12`	`+WHERE e.salary>e1.salary;`
`13`	`13`

Lines changed: 29 additions & 14 deletions

Original file line number	Diff line number	Diff line change
`@@ -1,17 +1,32 @@`
	`1`	`+/*`
`1`	`2`	`# Time: O(mlogn), m is the number of unique product id, n is the number of changed dates`
`2`	`3`	`# Space: O(m)`
	`4`	`+ */`
	`5`	`+`
	`6`	`+SELECT`
	`7`	`+ t1.product_id AS product_id,`
	`8`	`+ IF(ISNULL(t2.price), 10, t2.price) AS price`
	`9`	`+FROM`
	`10`	`+ (SELECT DISTINCT product_id`
	`11`	`+ FROM products) AS t1`
	`12`	`+LEFT JOIN`
	`13`	`+ (SELECT`
	`14`	`+ product_id,`
	`15`	`+ new_price AS price`
	`16`	`+ FROM`
	`17`	`+ products`
	`18`	`+ WHERE`
	`19`	`+ (product_id, change_date) IN`
	`20`	`+ (SELECT`
	`21`	`+ product_id,`
	`22`	`+ MAX(change_date)`
	`23`	`+ FROM`
	`24`	`+ products`
	`25`	`+ WHERE`
	`26`	`+ change_date <= '2019年08月16日'`
	`27`	`+ GROUP BY`
	`28`	`+ product_id)`
	`29`	`+ ) AS t2`
	`30`	`+ON`
	`31`	`+ t1.product_id = t2.product_id;`
`3`	`32`
`4`		`-SELECT t1.product_id AS product_id,`
`5`		`- IF(Isnull(t2.price), 10, t2.price) AS price`
`6`		`-FROM (SELECT DISTINCT product_id`
`7`		`- FROM products) AS t1`
`8`		`- left join (SELECT product_id,`
`9`		`- new_price AS price`
`10`		`- FROM products`
`11`		`- WHERE ( product_id, change_date ) IN (SELECT product_id,`
`12`		`- Max(change_date)`
`13`		`- FROM products`
`14`		`- WHERE change_date <= '2019年08月16日'`
`15`		`- GROUP BY product_id))`
`16`		`- AS t2`
`17`		`- ON t1.product_id = t2.product_id`

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