Commit d9f9111

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	`1`	`+#Task`
	`2`	`+#You are given a string. Split the string on a " " (space) delimiter and join using a - hyphen`
	`3`	`+`
	`4`	`+def split_and_join(line):`
	`5`	`+ s = ""`
	`6`	`+ s = line.split(" ")`
	`7`	`+ s = '-'.join(s)`
	`8`	`+ print(s)`
	`9`	`+split_and_join("praveen kumar srivas")`

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	`1`	`+# Output Format`
	`2`	`+`
	`3`	`+# Output the integer number indicating the total number of occurrences of the substring in the original string.`
	`4`	`+`
	`5`	`+# Sample Input`
	`6`	`+`
	`7`	`+# ABCDCDC`
	`8`	`+# CDC`
	`9`	`+# Sample Output`
	`10`	`+`
	`11`	`+# 2`
	`12`	`+`
	`13`	`+`
	`14`	`+def count_substring(string, sub_string):`
	`15`	`+ l = len(string)`
	`16`	`+ c = 0`
	`17`	`+ match = ""`
	`18`	`+ indx = 0`
	`19`	`+ x = 0`
	`20`	`+ z = 0`
	`21`	`+ for x in range(l):`
	`22`	`+ z = 0`
	`23`	`+ z = x`
	`24`	`+ for y in range(len(sub_string)):`
	`25`	`+ match += string[z]`
	`26`	`+ z += 1`
	`27`	`+ if (z > (l - 1)):`
	`28`	`+ break`
	`29`	`+ #print(z)`
	`30`	`+`
	`31`	`+ if (match == sub_string):`
	`32`	`+ c += 1`
	`33`	`+ z = 0`
	`34`	`+ match = ""`
	`35`	`+ else:`
	`36`	`+ match = ""`
	`37`	`+ z=0`
	`38`	`+`
	`39`	`+ return c`
	`40`	`+`
	`41`	`+`
	`42`	`+if __name__ == '__main__':`
	`43`	`+ string = input().strip()`
	`44`	`+ sub_string = input().strip()`
	`45`	`+`
	`46`	`+ count = count_substring(string, sub_string)`
	`47`	`+ print(count)`

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	`1`	`+`
	`2`	`+# In the Gregorian calendar three criteria must be taken into account to identify leap years:`
	`3`	`+`
	`4`	`+# The year can be evenly divided by 4, is a leap year, unless:`
	`5`	`+# The year can be evenly divided by 100, it is NOT a leap year, unless:`
	`6`	`+# The year is also evenly divisible by 400. Then it is a leap year.`
	`7`	`+`
	`8`	`+`
	`9`	`+def is_leap(year):`
	`10`	`+ year = int(year)`
	`11`	`+ leap = False`
	`12`	`+ if (year % 4 == 0 and (year % 100 != 0 and year % 400 == 0)):`
	`13`	`+ leap = True`
	`14`	`+ return leap`
	`15`	`+`
	`16`	`+`
	`17`	`+year = int(input())`
	`18`	`+print(is_leap(year))`

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	`1`	`+# Task`
	`2`	`+# Given an integer, , perform the following conditional actions:`
	`3`	`+`
	`4`	`+# If is odd, print Weird`
	`5`	`+# If is even and in the inclusive range of to, print Not Weird`
	`6`	`+# If is even and in the inclusive range of to, print Weird`
	`7`	`+# If is even and greater than, print Not Weird`
	`8`	`+`
	`9`	`+n = int(input())`
	`10`	`+if (n % 2 != 0):`
	`11`	`+ print('weird')`
	`12`	`+elif (n % 2 == 0 and n >= 2 and n <= 5):`
	`13`	`+ print('Not Weird')`
	`14`	`+elif (n % 2 == 0 and n >= 6 and n <= 20):`
	`15`	`+ print('weird')`
	`16`	`+else:`
	`17`	`+ print("Not Weird")`

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	`1`	`+# Sample Input:`
	`2`	`+ # abracadabra`
	`3`	`+ # 5 k`
	`4`	`+`
	`5`	`+# Sample Output:`
	`6`	`+ # abrackdabra`
	`7`	`+# Using any of the methods explained above, replace the character at index k with giving character .`
	`8`	`+`
	`9`	`+`
	`10`	`+def mutate_string(string, position, character):`
	`11`	`+ new = ""`
	`12`	`+ new=string[:position]+character+string[position+1:]`
	`13`	`+ return new`
	`14`	`+`
	`15`	`+`
	`16`	`+if __name__ == '__main__':`
	`17`	`+ s = input()`
	`18`	`+ i, c = input().split()`
	`19`	`+ s_new = mutate_string(s, int(i), c)`
	`20`	`+ print(s_new)`

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