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feat: add weekly contest 412 (doocs#3448)
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---
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comments: true
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difficulty: 简单
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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3200-3299/3264.Final%20Array%20State%20After%20K%20Multiplication%20Operations%20I/README.md
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---
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<!-- problem:start -->
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# [3264. K 次乘运算后的最终数组 I](https://leetcode.cn/problems/final-array-state-after-k-multiplication-operations-i)
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[English Version](/solution/3200-3299/3264.Final%20Array%20State%20After%20K%20Multiplication%20Operations%20I/README_EN.md)
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## 题目描述
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<!-- description:start -->
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<p>给你一个整数数组&nbsp;<code>nums</code>&nbsp;,一个整数&nbsp;<code>k</code>&nbsp;&nbsp;和一个整数&nbsp;<code>multiplier</code>&nbsp;。</p>
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<p>你需要对 <code>nums</code>&nbsp;执行 <code>k</code>&nbsp;次操作,每次操作中:</p>
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<ul>
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<li>找到 <code>nums</code>&nbsp;中的 <strong>最小</strong>&nbsp;值&nbsp;<code>x</code>&nbsp;,如果存在多个最小值,选择最 <strong>前面</strong>&nbsp;的一个。</li>
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<li>将 <code>x</code>&nbsp;替换为&nbsp;<code>x * multiplier</code>&nbsp;。</li>
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</ul>
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<p>请你返回执行完 <code>k</code>&nbsp;次乘运算之后,最终的 <code>nums</code>&nbsp;数组。</p>
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<p>&nbsp;</p>
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<p><strong class="example">示例 1:</strong></p>
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<div class="example-block">
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<p><span class="example-io"><b>输入:</b>nums = [2,1,3,5,6], k = 5, multiplier = 2</span></p>
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<p><span class="example-io"><b>输出:</b>[8,4,6,5,6]</span></p>
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<p><strong>解释:</strong></p>
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<table>
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<tbody>
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<tr>
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<th>操作</th>
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<th>结果</th>
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</tr>
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<tr>
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<td>1 次操作后</td>
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<td>[2, 2, 3, 5, 6]</td>
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</tr>
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<tr>
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<td>2 次操作后</td>
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<td>[4, 2, 3, 5, 6]</td>
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</tr>
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<tr>
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<td>3 次操作后</td>
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<td>[4, 4, 3, 5, 6]</td>
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</tr>
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<tr>
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<td>4 次操作后</td>
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<td>[4, 4, 6, 5, 6]</td>
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</tr>
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<tr>
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<td>5 次操作后</td>
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<td>[8, 4, 6, 5, 6]</td>
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</tr>
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</tbody>
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</table>
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</div>
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<p><strong class="example">示例 2:</strong></p>
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<div class="example-block">
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<p><span class="example-io"><b>输入:</b></span>nums = [1,2], k = 3, multiplier = 4</p>
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<p><span class="example-io"><b>输出:</b></span>[16,8]</p>
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<p><strong>解释:</strong></p>
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<table>
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<tbody>
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<tr>
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<th>操作</th>
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<th>结果</th>
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</tr>
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<tr>
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<td>1 次操作后</td>
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<td>[4, 2]</td>
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</tr>
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<tr>
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<td>2 次操作后</td>
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<td>[4, 8]</td>
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</tr>
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<tr>
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<td>3 次操作后</td>
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<td>[16, 8]</td>
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</tr>
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</tbody>
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</table>
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</div>
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<p>&nbsp;</p>
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<p><strong>提示:</strong></p>
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<ul>
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<li><code>1 &lt;= nums.length &lt;= 100</code></li>
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<li><code>1 &lt;= nums[i] &lt;= 100</code></li>
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<li><code>1 &lt;= k &lt;= 10</code></li>
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<li><code>1 &lt;= multiplier &lt;= 5</code></li>
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</ul>
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<!-- description:end -->
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## 解法
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<!-- solution:start -->
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### 方法一
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<!-- tabs:start -->
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#### Python3
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```python
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```
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#### Java
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```java
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```
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#### C++
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```cpp
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```
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#### Go
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```go
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```
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<!-- tabs:end -->
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<!-- solution:end -->
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<!-- problem:end -->
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---
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comments: true
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difficulty: Easy
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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3200-3299/3264.Final%20Array%20State%20After%20K%20Multiplication%20Operations%20I/README_EN.md
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---
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<!-- problem:start -->
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# [3264. Final Array State After K Multiplication Operations I](https://leetcode.com/problems/final-array-state-after-k-multiplication-operations-i)
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[中文文档](/solution/3200-3299/3264.Final%20Array%20State%20After%20K%20Multiplication%20Operations%20I/README.md)
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## Description
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<!-- description:start -->
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<p>You are given an integer array <code>nums</code>, an integer <code>k</code>, and an integer <code>multiplier</code>.</p>
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<p>You need to perform <code>k</code> operations on <code>nums</code>. In each operation:</p>
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<ul>
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<li>Find the <strong>minimum</strong> value <code>x</code> in <code>nums</code>. If there are multiple occurrences of the minimum value, select the one that appears <strong>first</strong>.</li>
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<li>Replace the selected minimum value <code>x</code> with <code>x * multiplier</code>.</li>
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</ul>
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<p>Return an integer array denoting the <em>final state</em> of <code>nums</code> after performing all <code>k</code> operations.</p>
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<p>&nbsp;</p>
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<p><strong class="example">Example 1:</strong></p>
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<div class="example-block">
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<p><strong>Input:</strong> <span class="example-io">nums = [2,1,3,5,6], k = 5, multiplier = 2</span></p>
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<p><strong>Output:</strong> <span class="example-io">[8,4,6,5,6]</span></p>
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<p><strong>Explanation:</strong></p>
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<table>
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<tbody>
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<tr>
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<th>Operation</th>
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<th>Result</th>
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</tr>
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<tr>
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<td>After operation 1</td>
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<td>[2, 2, 3, 5, 6]</td>
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</tr>
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<tr>
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<td>After operation 2</td>
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<td>[4, 2, 3, 5, 6]</td>
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</tr>
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<tr>
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<td>After operation 3</td>
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<td>[4, 4, 3, 5, 6]</td>
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</tr>
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<tr>
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<td>After operation 4</td>
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<td>[4, 4, 6, 5, 6]</td>
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</tr>
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<tr>
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<td>After operation 5</td>
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<td>[8, 4, 6, 5, 6]</td>
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</tr>
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</tbody>
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</table>
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</div>
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<p><strong class="example">Example 2:</strong></p>
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<div class="example-block">
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<p><strong>Input:</strong> <span class="example-io">nums = [1,2], k = 3, multiplier = 4</span></p>
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<p><strong>Output:</strong> <span class="example-io">[16,8]</span></p>
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<p><strong>Explanation:</strong></p>
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<table>
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<tbody>
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<tr>
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<th>Operation</th>
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<th>Result</th>
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</tr>
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<tr>
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<td>After operation 1</td>
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<td>[4, 2]</td>
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</tr>
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<tr>
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<td>After operation 2</td>
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<td>[4, 8]</td>
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</tr>
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<tr>
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<td>After operation 3</td>
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<td>[16, 8]</td>
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</tr>
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</tbody>
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</table>
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</div>
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<p>&nbsp;</p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li><code>1 &lt;= nums.length &lt;= 100</code></li>
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<li><code>1 &lt;= nums[i] &lt;= 100</code></li>
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<li><code>1 &lt;= k &lt;= 10</code></li>
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<li><code>1 &lt;= multiplier &lt;= 5</code></li>
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</ul>
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<!-- description:end -->
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## Solutions
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<!-- solution:start -->
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### Solution 1
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<!-- tabs:start -->
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#### Python3
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```python
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```
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#### Java
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```java
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```
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#### C++
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```cpp
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```
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#### Go
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```go
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```
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<!-- tabs:end -->
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<!-- solution:end -->
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<!-- problem:end -->

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