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Commit 78fe74b

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feat: add solutions to lc problem: No.1688
No.1688.Count of Matches in Tournament
1 parent 0744ae8 commit 78fe74b

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7 files changed

+102
-4
lines changed

7 files changed

+102
-4
lines changed

‎solution/1600-1699/1688.Count of Matches in Tournament/README.md‎

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<li><code>1 &lt;= n &lt;= 200</code></li>
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</ul>
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## 解法
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<!-- 这里可写通用的实现逻辑 -->
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n 个人比赛,最终淘汰 n - 1 个人,所以配对次数是 n - 1。
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<!-- tabs:start -->
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### **Python3**
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<!-- 这里可写当前语言的特殊实现逻辑 -->
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```python
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class Solution:
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def numberOfMatches(self, n: int) -> int:
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return n - 1
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```
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### **Java**
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<!-- 这里可写当前语言的特殊实现逻辑 -->
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```java
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class Solution {
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public int numberOfMatches(int n) {
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return n - 1;
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}
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}
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```
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### **C++**
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```cpp
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class Solution {
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public:
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int numberOfMatches(int n) {
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return n - 1;
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}
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};
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```
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### **Go**
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```go
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func numberOfMatches(n int) int {
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return n - 1
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}
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```
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### **JavaScript**
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```js
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/**
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* @param {number} n
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* @return {number}
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*/
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var numberOfMatches = function (n) {
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return n - 1;
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};
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```
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### **...**

‎solution/1600-1699/1688.Count of Matches in Tournament/README_EN.md‎

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@@ -46,21 +46,57 @@ Total number of matches = 7 +たす 3 +たす 2 +たす 1 =わ 13.
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<li><code>1 &lt;= n &lt;= 200</code></li>
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</ul>
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## Solutions
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<!-- tabs:start -->
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### **Python3**
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```python
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class Solution:
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def numberOfMatches(self, n: int) -> int:
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return n - 1
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```
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### **Java**
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```java
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class Solution {
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public int numberOfMatches(int n) {
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return n - 1;
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}
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}
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```
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### **C++**
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```cpp
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class Solution {
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public:
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int numberOfMatches(int n) {
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return n - 1;
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}
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};
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```
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### **Go**
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```go
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func numberOfMatches(n int) int {
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return n - 1
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}
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```
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### **JavaScript**
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```js
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/**
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* @param {number} n
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* @return {number}
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*/
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var numberOfMatches = function(n) {
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return n - 1;
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};
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```
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### **...**
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class Solution {
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public:
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int numberOfMatches(int n) {
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return n - 1;
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}
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};
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func numberOfMatches(n int) int {
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return n - 1
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}
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class Solution {
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public int numberOfMatches(int n) {
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return n - 1;
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}
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}
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/**
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* @param {number} n
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* @return {number}
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*/
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var numberOfMatches = function(n) {
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return n - 1;
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};
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class Solution:
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def numberOfMatches(self, n: int) -> int:
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return n - 1

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