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"Find Minimum in Rotated Sorted Array II"

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@@ -154,7 +154,7 @@ The `☢` means that you need to have a LeetCode Premium Subscription.
`154`	`154`	`\| 157 \| [Read N Characters Given Read4] ☢ \| \|`
`155`	`155`	`\| 156 \| [Binary Tree Upside Down] ☢ \| \|`
`156`	`156`	`\| 155 \| [Min Stack] \| [C](src/155.c) \|`
`157`		`-\| 154 \| [Find Minimum in Rotated Sorted Array II] \| \|`
	`157`	`+\| 154 \| [Find Minimum in Rotated Sorted Array II] \| [C](src/154.c) \|`
`158`	`158`	`\| 153 \| [Find Minimum in Rotated Sorted Array] \| [C](src/153.c) \|`
`159`	`159`	`\| 152 \| [Maximum Product Subarray] \| [C](src/152.c) \|`
`160`	`160`	`\| 151 \| [Reverse Words in a String] \| [C](src/151.c) \|`

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`@@ -0,0 +1,30 @@`
	`1`	`+#include <stdio.h>`
	`2`	`+#include <assert.h>`
	`3`	`+`
	`4`	`+int findMin(int *nums, int numsSize) {`
	`5`	`+ int l = 0;`
	`6`	`+ int r = numsSize - 1;`
	`7`	`+ while (l < r) {`
	`8`	`+ int m = l + (r - l) / 2;`
	`9`	`+ if (nums[l] > nums[m]) { /* right side is sorted */`
	`10`	`+ r = m;`
	`11`	`+ }`
	`12`	`+ else if (nums[r] < nums[m]) { /* left side is sorted */`
	`13`	`+ l = m + 1;`
	`14`	`+ }`
	`15`	`+ else { /* the sub-array is not rotated, 1 step to deal with dups */`
	`16`	`+ r--;`
	`17`	`+ }`
	`18`	`+ }`
	`19`	`+ return nums[l];`
	`20`	`+}`
	`21`	`+`
	`22`	`+int main() {`
	`23`	`+ int nums[] = { 3, 3, 1, 3 };`
	`24`	`+`
	`25`	`+ assert(findMin(nums, sizeof(nums) / sizeof(nums[0])) == 1);`
	`26`	`+`
	`27`	`+ printf("all tests passed!\n");`
	`28`	`+`
	`29`	`+ return 0;`
	`30`	`+}`

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