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| 1 | +<h2><a href="https://leetcode.com/problems/maximum-area-of-longest-diagonal-rectangle">Maximum Area of Longest Diagonal Rectangle</a></h2> <img src='https://img.shields.io/badge/Difficulty-Easy-brightgreen' alt='Difficulty: Easy' /><hr><p>You are given a 2D <strong>0-indexed </strong>integer array <code>dimensions</code>.</p> |
| 2 | + |
| 3 | +<p>For all indices <code>i</code>, <code>0 <= i < dimensions.length</code>, <code>dimensions[i][0]</code> represents the length and <code>dimensions[i][1]</code> represents the width of the rectangle<span style="font-size: 13.3333px;"> <code>i</code></span>.</p> |
| 4 | + |
| 5 | +<p>Return <em>the <strong>area</strong> of the rectangle having the <strong>longest</strong> diagonal. If there are multiple rectangles with the longest diagonal, return the area of the rectangle having the <strong>maximum</strong> area.</em></p> |
| 6 | + |
| 7 | +<p> </p> |
| 8 | +<p><strong class="example">Example 1:</strong></p> |
| 9 | + |
| 10 | +<pre> |
| 11 | +<strong>Input:</strong> dimensions = [[9,3],[8,6]] |
| 12 | +<strong>Output:</strong> 48 |
| 13 | +<strong>Explanation:</strong> |
| 14 | +For index = 0, length = 9 and width = 3. Diagonal length = sqrt(9 * 9 + 3 * 3) = sqrt(90) ≈<!-- notionvc: 882cf44c-3b17-428e-9c65-9940810216f1 --> 9.487. |
| 15 | +For index = 1, length = 8 and width = 6. Diagonal length = sqrt(8 * 8 + 6 * 6) = sqrt(100) = 10. |
| 16 | +So, the rectangle at index 1 has a greater diagonal length therefore we return area = 8 * 6 = 48. |
| 17 | +</pre> |
| 18 | + |
| 19 | +<p><strong class="example">Example 2:</strong></p> |
| 20 | + |
| 21 | +<pre> |
| 22 | +<strong>Input:</strong> dimensions = [[3,4],[4,3]] |
| 23 | +<strong>Output:</strong> 12 |
| 24 | +<strong>Explanation:</strong> Length of diagonal is the same for both which is 5, so maximum area = 12. |
| 25 | +</pre> |
| 26 | + |
| 27 | +<p> </p> |
| 28 | +<p><strong>Constraints:</strong></p> |
| 29 | + |
| 30 | +<ul> |
| 31 | + <li><code>1 <= dimensions.length <= 100</code></li> |
| 32 | + <li><code><font face="monospace">dimensions[i].length == 2</font></code></li> |
| 33 | + <li><code><font face="monospace">1 <= dimensions[i][0], dimensions[i][1] <= 100</font></code></li> |
| 34 | +</ul> |
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