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Commit 2eb27c7

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update 1022.sum-of-root-to-leaf-binary-numbers.java
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/*
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* @lc app=leetcode id=1022 lang=java
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*
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* [1022] Sum of Root To Leaf Binary Numbers
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*
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* https://leetcode.com/problems/sum-of-root-to-leaf-binary-numbers/description/
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*
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* algorithms
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* Easy (65.39%)
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* Likes: 380
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* Dislikes: 66
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* Total Accepted: 33.7K
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* Total Submissions: 51.6K
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* Testcase Example: '[1,0,1,0,1,0,1]'
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*
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* Given a binary tree, each node has value 0 or 1. Each root-to-leaf path
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* represents a binary number starting with the most significant bit. For
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* example, if the path is 0 -> 1 -> 1 -> 0 -> 1, then this could represent
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* 01101 in binary, which is 13.
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*
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* For all leaves in the tree, consider the numbers represented by the path
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* from the root to that leaf.
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*
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* Return the sum of these numbers.
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*
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*
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*
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* Example 1:
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*
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*
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*
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*
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* Input: [1,0,1,0,1,0,1]
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* Output: 22
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* Explanation: (100) + (101) + (110) + (111) = 4 +たす 5 +たす 6 +たす 7 = 22
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*
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*
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*
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*
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* Note:
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*
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*
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* The number of nodes in the tree is between 1 and 1000.
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* node.val is 0 or 1.
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* The answer will not exceed 2^31 - 1.
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*
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*
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*/
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// @lc code=start
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/**
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* Definition for a binary tree node.
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* public class TreeNode {
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* int val;
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* TreeNode left;
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* TreeNode right;
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* TreeNode(int x) { val = x; }
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* }
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*/
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class Solution {
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int callme(int cur, TreeNode root){
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if(root == null)
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return 0;
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cur = cur*2 + root.val;
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if(root.left == null && root.right == null)
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return cur;
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return callme(cur, root.left) + callme(cur, root.right);
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}
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public int sumRootToLeaf(TreeNode root) {
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return callme(0, root);
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}
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}
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// @lc code=end

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