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Commit 4f4f837

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add: Spiral Matrix
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‎README.md‎

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@@ -22,6 +22,7 @@ This is the solutions collection of my LeetCode submissions, most of them are pr
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|33|[Search in Rotated Sorted Array](https://leetcode.com/problems/search-in-rotated-sorted-array/) | [JavaScript](./src/search-in-rotated-sorted-array/res.js)|Medium|
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|34|[Search for a Range](https://leetcode.com/problems/search-for-a-range/) | [JavaScript](./src/search-for-a-range/res.js)|Medium|
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|48|[Rotate Image](https://leetcode.com/problems/rotate-image/) | [JavaScript](./src/rotate-image/res.js)|Medium|
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|54|[Spiral Matrix](https://leetcode.com/problems/spiral-matrix/) | [JavaScript](./src/spiral-matrix/res.js)|Medium|
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|66|[Plus One](https://leetcode.com/problems/plus-one/) | [JavaScript](./src/plus-one/res.js)|Easy|
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|69|[Sqrt(x)](https://leetcode.com/problems/sqrtx/) | [JavaScript](./src/sqrtx/res.js)|Easy|
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|73|[Set Matrix Zeroes](https://leetcode.com/problems/set-matrix-zeroes/) | [JavaScript](./src/set-matrix-zeroes/res.js)|Medium|

‎src/spiral-matrix/res.js‎

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/**
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* Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order.
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*
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* For example,
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*
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* Given the following matrix:
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* [
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* [ 1, 2, 3 ],
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* [ 4, 5, 6 ],
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* [ 7, 8, 9 ]
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* ]
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*
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* You should return [1,2,3,6,9,8,7,4,5].
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*
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* res.js
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* @authors Joe Jiang (hijiangtao@gmail.com)
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* @date 2017年03月03日 21:42:58
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* @version $Id$
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*
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* @param {number[][]} matrix
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* @return {number[]}
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*/
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let spiralOrder = function(matrix) {
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if (matrix.length === 0) {
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return matrix;
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}
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let rowBegin = 0,
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rowEnd = matrix.length-1,
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colBegin = 0,
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colEnd = matrix[0].length-1,
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res =[];
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while (rowBegin <= rowEnd || colBegin <= colEnd) {
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// left->right
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for (let i=colBegin; i<=colEnd; i++) {
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res.push( matrix[rowBegin][i] );
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}
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if (rowBegin === rowEnd) {
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break;
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}
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// right->bottom
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rowBegin++;
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for (let i=rowBegin; i<=rowEnd; i++) {
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res.push( matrix[i][colEnd] );
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}
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if (colBegin === colEnd) {
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break;
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}
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// bottom->left
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colEnd--;
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for (let i=colEnd; i>=colBegin; i--) {
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res.push( matrix[rowEnd][i] );
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}
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if (rowBegin === rowEnd) {
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break;
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}
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// left bottom->top
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rowEnd--;
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for (let i=rowEnd; i>=rowBegin; i--) {
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res.push( matrix[i][colBegin] );
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}
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if (colBegin === colEnd) {
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break;
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}
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colBegin++;
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}
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return res;
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};

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