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Commit f67f6c0

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feat: update sql solution to lc problem: No.0615,0618 (doocs#1193)
* No.0615.Average Salary Departments VS Company * No.0618.Students Report By Geography
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6 files changed

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6 files changed

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‎solution/0600-0699/0615.Average Salary Departments VS Company/README.md‎

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@@ -105,4 +105,35 @@ SELECT DISTINCT
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FROM t;
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```
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```sql
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# Write your MySQL query statement below
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WITH
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S AS (
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SELECT *
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FROM
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Salary
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JOIN Employee USING (employee_id)
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),
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T AS (
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SELECT
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date_format(pay_date, '%Y-%m') AS pay_month,
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department_id,
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avg(amount) OVER (
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PARTITION BY pay_date, department_id
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) AS department_avg,
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avg(amount) OVER (PARTITION BY pay_date) AS company_avg
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FROM S
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)
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SELECT
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pay_month,
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department_id,
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CASE
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WHEN avg(department_avg) > avg(company_avg) THEN 'higher'
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WHEN avg(department_avg) < avg(company_avg) THEN 'lower'
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ELSE 'same'
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END AS comparison
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FROM T
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GROUP BY 1, 2;
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```
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<!-- tabs:end -->

‎solution/0600-0699/0615.Average Salary Departments VS Company/README_EN.md‎

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@@ -116,4 +116,35 @@ SELECT DISTINCT
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FROM t;
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```
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```sql
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# Write your MySQL query statement below
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WITH
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S AS (
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SELECT *
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FROM
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Salary
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JOIN Employee USING (employee_id)
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),
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T AS (
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SELECT
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date_format(pay_date, '%Y-%m') AS pay_month,
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department_id,
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avg(amount) OVER (
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PARTITION BY pay_date, department_id
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) AS department_avg,
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avg(amount) OVER (PARTITION BY pay_date) AS company_avg
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FROM S
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)
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SELECT
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pay_month,
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department_id,
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CASE
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WHEN avg(department_avg) > avg(company_avg) THEN 'higher'
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WHEN avg(department_avg) < avg(company_avg) THEN 'lower'
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ELSE 'same'
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END AS comparison
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FROM T
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GROUP BY 1, 2;
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```
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<!-- tabs:end -->
Lines changed: 16 additions & 11 deletions
Original file line numberDiff line numberDiff line change
@@ -1,23 +1,28 @@
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# Write your MySQL query statement below
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WITH
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t AS (
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S AS (
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SELECT *
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FROM
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Salary
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JOIN Employee USING (employee_id)
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),
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T AS (
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SELECT
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date_format(pay_date, '%Y-%m') AS pay_month,
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department_id,
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avg(amount) OVER (PARTITION BY pay_date) AS company_avg_amount,
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avg(amount) OVER (
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PARTITION BY pay_date, department_id
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) AS department_avg_amount
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FROM
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Salary AS s
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JOIN Employee AS e ON s.employee_id = e.employee_id
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) AS department_avg,
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avg(amount) OVER (PARTITION BY pay_date) AS company_avg
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FROM S
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)
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SELECT DISTINCT
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SELECT
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pay_month,
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department_id,
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CASE
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WHEN company_avg_amount = department_avg_amount THEN 'same'
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WHEN company_avg_amount < department_avg_amount THEN 'higher'
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ELSE 'lower'
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WHEN avg(department_avg) >avg(company_avg) THEN 'higher'
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WHEN avg(department_avg) < avg(company_avg) THEN 'lower'
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ELSE 'same'
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END AS comparison
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FROM t;
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FROM T
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GROUP BY 1, 2;

‎solution/0600-0699/0618.Students Report By Geography/README.md‎

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@@ -60,31 +60,32 @@ Student table:
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<!-- 这里可写通用的实现逻辑 -->
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**方法一:窗口函数 + GROUP BY**
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我们可以使用窗口函数 `row_number()` 来为每个大洲的学生编号,然后使用 `GROUP BY` 来将同一编号的学生聚合到一行中。
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<!-- tabs:start -->
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### **SQL**
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```sql
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# Write your MySQL query statement below
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with t as (
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select
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*,
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row_number() over(
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partition by continent
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order by
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name
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) rn
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from
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Student
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)
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select
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max(if(continent = 'America', name, null)) America,
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max(if(continent = 'Asia', name, null)) Asia,
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max(if(continent = 'Europe', name, null)) Europe
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from
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t
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group by
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rn
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WITH
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T AS (
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SELECT
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*,
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row_number() OVER (
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PARTITION BY continent
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ORDER BY name
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) AS rk
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FROM Student
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)
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SELECT
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max(if(continent = 'America', name, NULL)) AS 'America',
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max(if(continent = 'Asia', name, NULL)) AS 'Asia',
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max(if(continent = 'Europe', name, NULL)) AS 'Europe'
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FROM T
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GROUP BY rk;
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```
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<!-- tabs:end -->

‎solution/0600-0699/0618.Students Report By Geography/README_EN.md‎

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@@ -61,25 +61,22 @@ Student table:
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```sql
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# Write your MySQL query statement below
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with t as (
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select
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*,
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row_number() over(
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partition by continent
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order by
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name
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) rn
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from
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Student
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)
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select
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max(if(continent = 'America', name, null)) America,
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max(if(continent = 'Asia', name, null)) Asia,
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max(if(continent = 'Europe', name, null)) Europe
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from
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t
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group by
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rn
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WITH
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T AS (
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SELECT
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*,
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row_number() OVER (
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PARTITION BY continent
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ORDER BY name
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) AS rk
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FROM Student
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)
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SELECT
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max(if(continent = 'America', name, NULL)) AS 'America',
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max(if(continent = 'Asia', name, NULL)) AS 'Asia',
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max(if(continent = 'Europe', name, NULL)) AS 'Europe'
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FROM T
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GROUP BY rk;
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```
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<!-- tabs:end -->
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Original file line numberDiff line numberDiff line change
@@ -1,17 +1,17 @@
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# Write your MySQL query statement below
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WITH
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t AS (
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T AS (
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SELECT
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*,
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row_number() OVER (
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PARTITION BY continent
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ORDER BY name
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) AS rn
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) AS rk
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FROM Student
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)
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SELECT
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max(if(continent = 'America', name, NULL)) AS America,
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max(if(continent = 'Asia', name, NULL)) AS Asia,
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max(if(continent = 'Europe', name, NULL)) AS Europe
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FROM t
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GROUP BY rn;
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max(if(continent = 'America', name, NULL)) AS 'America',
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max(if(continent = 'Asia', name, NULL)) AS 'Asia',
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max(if(continent = 'Europe', name, NULL)) AS 'Europe'
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FROM T
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GROUP BY rk;

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