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Commit a2f6ec2

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feat: update sql solutions to lc problems (doocs#1174)
1 parent b9f98f0 commit a2f6ec2

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15 files changed

+108
-107
lines changed

15 files changed

+108
-107
lines changed

‎solution/0100-0199/0183.Customers Who Never Order/README.md‎

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Original file line numberDiff line numberDiff line change
@@ -57,22 +57,23 @@
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### **SQL**
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```sql
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SELECT Name AS Customers
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# Write your MySQL query statement below
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SELECT name AS Customers
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FROM Customers
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WHERE
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id NOT IN (
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SELECT CustomerId
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SELECT customerId
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FROM Orders
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);
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```
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```sql
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SELECT
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c.Name AS Customers
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# Write your MySQL query statement below
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SELECT name AS Customers
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FROM
73-
customers AS c
74-
LEFT JOIN orders AS o ON c.Id = o.CustomerId
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WHERE o.CustomerId IS NULL;
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Customers AS c
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LEFT JOIN Orders AS o ON c.id = o.customerId
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WHERE o.id IS NULL;
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```
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<!-- tabs:end -->

‎solution/0100-0199/0183.Customers Who Never Order/README_EN.md‎

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Original file line numberDiff line numberDiff line change
@@ -78,22 +78,23 @@ Orders table:
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### **SQL**
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```sql
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SELECT Name AS Customers
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# Write your MySQL query statement below
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SELECT name AS Customers
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FROM Customers
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WHERE
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id NOT IN (
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SELECT CustomerId
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SELECT customerId
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FROM Orders
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);
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```
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```sql
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SELECT
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c.Name AS Customers
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# Write your MySQL query statement below
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SELECT name AS Customers
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FROM
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customers AS c
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LEFT JOIN orders AS o ON c.Id = o.CustomerId
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WHERE o.CustomerId IS NULL;
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Customers AS c
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LEFT JOIN Orders AS o ON c.id = o.customerId
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WHERE o.id IS NULL;
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```
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<!-- tabs:end -->
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Original file line numberDiff line numberDiff line change
@@ -1,7 +1,8 @@
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SELECT Name AS Customers
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# Write your MySQL query statement below
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SELECT name AS Customers
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FROM Customers
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WHERE
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id NOT IN (
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SELECT CustomerId
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SELECT customerId
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FROM Orders
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);

‎solution/0100-0199/0184.Department Highest Salary/README.md‎

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@@ -122,23 +122,18 @@ WHERE
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```sql
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# Write your MySQL query statement below
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WITH
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t AS (
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T AS (
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SELECT
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departmentId,
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name,
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salary,
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*,
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rank() OVER (
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PARTITION BY departmentId
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ORDER BY salary DESC
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) AS rk
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FROM Employee
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)
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SELECT
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d.name AS Department,
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t.name AS Employee,
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salary AS Salary
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SELECT d.name AS Department, t.name AS Employee, salary AS Salary
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FROM
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t
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T ASt
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JOIN Department AS d ON t.departmentId = d.id
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WHERE rk = 1;
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```

‎solution/0100-0199/0184.Department Highest Salary/README_EN.md‎

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@@ -120,23 +120,18 @@ WHERE
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```sql
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# Write your MySQL query statement below
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WITH
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t AS (
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T AS (
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SELECT
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departmentId,
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name,
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salary,
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*,
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rank() OVER (
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PARTITION BY departmentId
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ORDER BY salary DESC
131129
) AS rk
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FROM Employee
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)
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SELECT
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d.name AS Department,
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t.name AS Employee,
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salary AS Salary
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SELECT d.name AS Department, t.name AS Employee, salary AS Salary
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FROM
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t
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T ASt
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JOIN Department AS d ON t.departmentId = d.id
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WHERE rk = 1;
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```
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Original file line numberDiff line numberDiff line change
@@ -1,21 +1,16 @@
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# Write your MySQL query statement below
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WITH
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t AS (
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T AS (
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SELECT
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departmentId,
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name,
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salary,
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*,
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rank() OVER (
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PARTITION BY departmentId
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ORDER BY salary DESC
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) AS rk
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FROM Employee
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)
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SELECT
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d.name AS Department,
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t.name AS Employee,
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salary AS Salary
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SELECT d.name AS Department, t.name AS Employee, salary AS Salary
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FROM
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t
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T ASt
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JOIN Department AS d ON t.departmentId = d.id
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WHERE rk = 1;

‎solution/0100-0199/0185.Department Top Three Salaries/README.md‎

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@@ -125,25 +125,20 @@ WHERE
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```sql
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# Write your MySQL query statement below
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WITH
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t AS (
128+
T AS (
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SELECT
130-
departmentId,
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name,
132-
salary,
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*,
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dense_rank() OVER (
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PARTITION BY departmentId
135133
ORDER BY salary DESC
136134
) AS rk
137135
FROM Employee
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)
139-
SELECT
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d.name AS Department,
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t.name AS Employee,
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salary AS Salary
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SELECT d.name AS Department, t.name AS Employee, salary AS Salary
143138
FROM
144-
t
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T ASt
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JOIN Department AS d ON t.departmentId = d.id
146-
WHERE rk <4;
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WHERE rk <=3;
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```
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<!-- tabs:end -->

‎solution/0100-0199/0185.Department Top Three Salaries/README_EN.md‎

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Original file line numberDiff line numberDiff line change
@@ -121,25 +121,20 @@ WHERE
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```sql
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# Write your MySQL query statement below
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WITH
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t AS (
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T AS (
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SELECT
126-
departmentId,
127-
name,
128-
salary,
126+
*,
129127
dense_rank() OVER (
130128
PARTITION BY departmentId
131129
ORDER BY salary DESC
132130
) AS rk
133131
FROM Employee
134132
)
135-
SELECT
136-
d.name AS Department,
137-
t.name AS Employee,
138-
salary AS Salary
133+
SELECT d.name AS Department, t.name AS Employee, salary AS Salary
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FROM
140-
t
135+
T ASt
141136
JOIN Department AS d ON t.departmentId = d.id
142-
WHERE rk <4;
137+
WHERE rk <=3;
143138
```
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<!-- tabs:end -->
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Original file line numberDiff line numberDiff line change
@@ -1,21 +1,16 @@
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# Write your MySQL query statement below
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WITH
3-
t AS (
3+
T AS (
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SELECT
5-
departmentId,
6-
name,
7-
salary,
5+
*,
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dense_rank() OVER (
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PARTITION BY departmentId
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ORDER BY salary DESC
119
) AS rk
1210
FROM Employee
1311
)
14-
SELECT
15-
d.name AS Department,
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t.name AS Employee,
17-
salary AS Salary
12+
SELECT d.name AS Department, t.name AS Employee, salary AS Salary
1813
FROM
19-
t
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T ASt
2015
JOIN Department AS d ON t.departmentId = d.id
21-
WHERE rk <4;
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WHERE rk <=3;

‎solution/0100-0199/0196.Delete Duplicate Emails/README.md‎

Lines changed: 21 additions & 5 deletions
Original file line numberDiff line numberDiff line change
@@ -61,13 +61,29 @@ Person 表:
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### **SQL**
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```sql
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# Write your MySQL query statement below
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DELETE FROM Person
6566
WHERE
66-
Id NOT IN (
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SELECT
68-
MIN(Id)
69-
FROM (SELECT * FROM Person) AS p
70-
GROUP BY p.Email
67+
id NOT IN (SELECT min(id) FROM (SELECT * FROM Person) AS p GROUP BY email);
68+
```
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```sql
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# Write your MySQL query statement below
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DELETE FROM Person
73+
WHERE
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id NOT IN (
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SELECT id
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FROM
77+
(
78+
SELECT
79+
id,
80+
row_number() OVER (
81+
PARTITION BY email
82+
ORDER BY id
83+
) AS rk
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FROM Person
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) AS p
86+
WHERE rk = 1
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);
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```
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