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Commit 25690c9

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Sync LeetCode submission Runtime - 0 ms (100.00%), Memory - 17.9 MB (26.17%)
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<p>Given <code>head</code> which is a reference node to a singly-linked list. The value of each node in the linked list is either <code>0</code> or <code>1</code>. The linked list holds the binary representation of a number.</p>
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<p>Return the <em>decimal value</em> of the number in the linked list.</p>
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<p>The <strong>most significant bit</strong> is at the head of the linked list.</p>
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<p>&nbsp;</p>
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<p><strong class="example">Example 1:</strong></p>
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<img alt="" src="https://assets.leetcode.com/uploads/2019/12/05/graph-1.png" style="width: 426px; height: 108px;" />
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<pre>
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<strong>Input:</strong> head = [1,0,1]
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<strong>Output:</strong> 5
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<strong>Explanation:</strong> (101) in base 2 = (5) in base 10
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</pre>
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<p><strong class="example">Example 2:</strong></p>
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<pre>
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<strong>Input:</strong> head = [0]
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<strong>Output:</strong> 0
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</pre>
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<p>&nbsp;</p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li>The Linked List is not empty.</li>
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<li>Number of nodes will not exceed <code>30</code>.</li>
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<li>Each node&#39;s value is either <code>0</code> or <code>1</code>.</li>
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</ul>
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# Approach 2: Bit Manipulation
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# Time: O(n)
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# Space: O(1)
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# Definition for singly-linked list.
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# class ListNode:
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# def __init__(self, val=0, next=None):
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# self.val = val
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# self.next = next
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class Solution:
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def getDecimalValue(self, head: Optional[ListNode]) -> int:
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num = head.val
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while head.next:
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num = (num << 1) | head.next.val
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head = head.next
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return num

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