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Commit f414bf5

Browse files
authored
Improved tasks 175-184
1 parent c7aa0c5 commit f414bf5

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8 files changed

+76
-32
lines changed

8 files changed

+76
-32
lines changed
Lines changed: 10 additions & 2 deletions
Original file line numberDiff line numberDiff line change
@@ -1,4 +1,12 @@
11
# Write your MySQL query statement below
22
# #Easy #Database #SQL_I_Day_5_Union #2022_06_26_Time_491_ms_(32.30%)_Space_0B_(100.00%)
3-
SELECT FirstName, LastName, City, State
4-
FROM Person LEFT JOIN Address USING (PersonId)
3+
SELECT
4+
FirstName,
5+
LastName,
6+
City,
7+
State
8+
FROM
9+
Person
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LEFT JOIN
11+
Address
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USING (PersonId);
Lines changed: 10 additions & 6 deletions
Original file line numberDiff line numberDiff line change
@@ -1,9 +1,13 @@
11
# Write your MySQL query statement below
22
# #Medium #Database #SQL_I_Day_4_Union_and_Select
33
# #2022_07_10_Time_225_ms_(73.10%)_Space_0B_(100.00%)
4-
SELECT ifnull(
5-
(SELECT distinct(Salary)
6-
FROM Employee
7-
ORDER BY Salary DESC
8-
LIMIT 1
9-
OFFSET 1), NULL) SecondHighestSalary;
4+
SELECT
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IFNULL(
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(
7+
SELECT DISTINCT Salary
8+
FROM Employee
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ORDER BY Salary DESC
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LIMIT 1 OFFSET 1
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),
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NULL
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) AS SecondHighestSalary;
Lines changed: 8 additions & 1 deletion
Original file line numberDiff line numberDiff line change
@@ -1,3 +1,10 @@
11
# Write your MySQL query statement below
22
# #Medium #Database #2022_06_26_Time_290_ms_(66.73%)_Space_0B_(100.00%)
3-
select Score, DENSE_RANK() OVER(order by Score Desc) as "Rank" from Scores order by "Rank" Asc;
3+
SELECT
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Score,
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DENSE_RANK() OVER (ORDER BY Score DESC) AS Rank
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FROM
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Scores
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ORDER BY
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Rank ASC;
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Lines changed: 9 additions & 5 deletions
Original file line numberDiff line numberDiff line change
@@ -1,7 +1,11 @@
11
# Write your MySQL query statement below
22
# #Medium #Database #2024_07_15_Time_469_ms_(89.19%)_Space_0B_(100.00%)
3-
SELECT DISTINCT l1.num AS ConsecutiveNums
4-
FROM Logs l1
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JOIN Logs l2 ON l1.id = l2.id - 1
6-
JOIN Logs l3 ON l1.id = l3.id - 2
7-
WHERE l1.num = l2.num AND l2.num = l3.num;
3+
SELECT DISTINCT
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l1.num AS ConsecutiveNums
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FROM
6+
Logs l1
7+
JOIN Logs l2 ON l1.id = l2.id - 1
8+
JOIN Logs l3 ON l1.id = l3.id - 2
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WHERE
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l1.num = l2.num
11+
AND l2.num = l3.num;
Lines changed: 8 additions & 2 deletions
Original file line numberDiff line numberDiff line change
@@ -1,4 +1,10 @@
11
# Write your MySQL query statement below
22
# #Easy #Database #2022_06_27_Time_315_ms_(94.44%)_Space_0B_(100.00%)
3-
select a.Name as Employee from Employee a left join Employee b on a.ManagerId=b.Id
4-
where a.Salary > b.Salary and a.ManagerId is not null
3+
SELECT
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a.Name AS Employee
5+
FROM
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Employee a
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LEFT JOIN Employee b ON a.ManagerId = b.Id
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WHERE
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a.Salary > b.Salary
10+
AND a.ManagerId IS NOT NULL;
Lines changed: 9 additions & 1 deletion
Original file line numberDiff line numberDiff line change
@@ -1,3 +1,11 @@
11
# Write your MySQL query statement below
22
# #Easy #Database #SQL_I_Day_10_Where #2022_06_27_Time_303_ms_(92.08%)_Space_0B_(100.00%)
3-
SELECT Email FROM Person GROUP BY Email HAVING COUNT(Email) > 1;
3+
SELECT
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Email
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FROM
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Person
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GROUP BY
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Email
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HAVING
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COUNT(Email) > 1;
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Lines changed: 7 additions & 5 deletions
Original file line numberDiff line numberDiff line change
@@ -1,7 +1,9 @@
11
# Write your MySQL query statement below
22
# #Easy #Database #SQL_I_Day_1_Select #2022_06_27_Time_376_ms_(98.73%)_Space_0B_(100.00%)
3-
SELECT c.Name as Customers
4-
FROM Customers as c
5-
LEFT JOIN Orders as o
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ON c.Id = o.CustomerId
7-
WHERE o.CustomerId is null
3+
SELECT
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c.Name AS Customers
5+
FROM
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Customers AS c
7+
LEFT JOIN Orders AS o ON c.Id = o.CustomerId
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WHERE
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o.CustomerId IS NULL;

‎src/main/java/g0101_0200/s0184_department_highest_salary/script.sql

Lines changed: 15 additions & 10 deletions
Original file line numberDiff line numberDiff line change
@@ -5,13 +5,18 @@ SELECT
55
Sel.Name AS Employee,
66
Sel.Salary AS Salary
77
FROM
8-
(
9-
SELECT
10-
Name,
11-
Salary,
12-
DepartmentId,
13-
DENSE_RANK() OVER (PARTITION BY DepartmentId ORDER BY Salary DESC) AS dr
14-
FROM Employee
15-
) AS Sel
16-
INNER JOIN Department d ON d.Id = Sel.DepartmentId
17-
WHERE Sel.dr = 1
8+
(
9+
SELECT
10+
Name,
11+
Salary,
12+
DepartmentId,
13+
DENSE_RANK() OVER (
14+
PARTITION BY DepartmentId
15+
ORDER BY Salary DESC
16+
) AS dr
17+
FROM
18+
Employee
19+
) AS Sel
20+
INNER JOIN Department d ON d.Id = Sel.DepartmentId
21+
WHERE
22+
Sel.dr = 1;

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