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8 | 8 | "Print the following pattern for the given number of rows.<br>\n", |
9 | 9 | "Note: N is always odd.<br>\n", |
10 | 10 | "Pattern for N = 5<br>\n", |
11 | | - "<br>\n", |
| 11 | + "<br>\n", |
12 | 12 | "The dots represent spaces.<br>\n", |
13 | 13 | "Input format :<br>\n", |
14 | 14 | "N (Total no. of rows and can only be odd)<br>\n", |
|
67 | 67 | " print()\n", |
68 | 68 | " currRow-=1" |
69 | 69 | ] |
| 70 | + }, |
| 71 | + { |
| 72 | + "cell_type": "code", |
| 73 | + "execution_count": 1, |
| 74 | + "metadata": {}, |
| 75 | + "outputs": [ |
| 76 | + { |
| 77 | + "name": "stdout", |
| 78 | + "output_type": "stream", |
| 79 | + "text": [ |
| 80 | + "9\n", |
| 81 | + " *\n", |
| 82 | + " ***\n", |
| 83 | + " *****\n", |
| 84 | + " *******\n", |
| 85 | + "*********\n", |
| 86 | + " *******\n", |
| 87 | + " *****\n", |
| 88 | + " ***\n", |
| 89 | + " *\n" |
| 90 | + ] |
| 91 | + } |
| 92 | + ], |
| 93 | + "source": [ |
| 94 | + "#Another Solution\n", |
| 95 | + "n=int(input())\n", |
| 96 | + "first=n//2+1\n", |
| 97 | + "sec=n//2\n", |
| 98 | + "#first loop\n", |
| 99 | + "for i in range(1,first+1):\n", |
| 100 | + " print(\" \"*(first-i),end=\"\")\n", |
| 101 | + " print((2*i-1)*\"*\",end=\"\")\n", |
| 102 | + " print()\n", |
| 103 | + "#Second Loop\n", |
| 104 | + "for p in range(1,sec+1):\n", |
| 105 | + " print(\" \"*p,end=\"\")\n", |
| 106 | + " print((2*(sec-p+1)-1)*\"*\",end=\"\")\n", |
| 107 | + " print()" |
| 108 | + ] |
70 | 109 | } |
71 | 110 | ], |
72 | 111 | "metadata": { |
|
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