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LeetCode SQL 50 #22

Answered by iamAntimPal
IamShiwangi asked this question in Q&A
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# Write your MySQL query statement below
WITH
 S AS (
 SELECT 'Low Salary' AS category
 UNION
 SELECT 'Average Salary'
 UNION
 SELECT 'High Salary'
 ),
 T AS (
 SELECT
 CASE
 WHEN income < 20000 THEN "Low Salary"
 WHEN income > 50000 THEN 'High Salary'
 ELSE 'Average Salary'
 END AS category,
 COUNT(1) AS accounts_count
 FROM Accounts
 GROUP BY 1
 )
SELECT category, IFNULL(accounts_count, 0) AS accounts_count
FROM
 S
 LEFT JOIN T USING (category);

For Explanation got to 1907. Count Salary Categories

Replies: 2 comments 1 reply

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# Write your MySQL query statement below
WITH
 S AS (
 SELECT 'Low Salary' AS category
 UNION
 SELECT 'Average Salary'
 UNION
 SELECT 'High Salary'
 ),
 T AS (
 SELECT
 CASE
 WHEN income < 20000 THEN "Low Salary"
 WHEN income > 50000 THEN 'High Salary'
 ELSE 'Average Salary'
 END AS category,
 COUNT(1) AS accounts_count
 FROM Accounts
 GROUP BY 1
 )
SELECT category, IFNULL(accounts_count, 0) AS accounts_count
FROM
 S
 LEFT JOIN T USING (category);

For Explanation got to 1907. Count Salary Categories

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1 reply
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Thank you so much sir

Answer selected by IamShiwangi
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i understand all of that

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