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[basicTypes] Remove confusing statement about operator precedence.

The question was about boolean logic, and not precedences.

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Lines changed: 1 addition & 1 deletion

Original file line number	Diff line number	Diff line change
`@@ -45,7 +45,7 @@ int main() {`
`45`	`45`	`bool condition1 = false;`
`46`	`46`	`bool condition2 = true;`
`47`	`47`	`print( alwaysTrue && condition1 && condition2 );`
`48`		`- print( alwaysTrue \|\| condition1 && condition2 ); // Q: Why does operator precedence render this expression useless?`
	`48`	`+ print( alwaysTrue \|\| condition1 && condition2 ); // Q: Are this and the following expressions useful?`
`49`	`49`	`print( alwaysTrue && condition1 \|\| condition2 );`
`50`	`50`	`print(condition1 != condition1); // Q: What is the difference between this and the following expression?`
`51`	`51`	`print(condition2 = !condition2);`

Lines changed: 3 additions & 2 deletions

Original file line number	Diff line number	Diff line change
`@@ -45,8 +45,9 @@ int main() {`
`45`	`45`	`bool condition1 = false;`
`46`	`46`	`bool condition2 = true;`
`47`	`47`	`print( alwaysTrue && condition1 && condition2 );`
`48`		`- print( alwaysTrue \|\| condition1 && condition2 ); // Q: Why does operator precedence render this expression useless?`
`49`		`- print( alwaysTrue && condition1 \|\| condition2 ); // A: "true \|\| " is evaluated last. The expression therefore is always true.`
	`48`	`+ print( alwaysTrue \|\| condition1 && condition2 ); // Q: Are this and the following expressions useful?`
	`49`	`+ // A: Not really. Since we use "true \|\|", it is always true.`
	`50`	`+ print( alwaysTrue && condition1 \|\| condition2 ); // A: "true && condition1" is the same as "condition1"`
`50`	`51`	`print(condition1 != condition1); // Q: What is the difference between this and the following expression?`
`51`	`52`	`print(condition2 = !condition2); // A: The first is a comparison, the second a negation with subsequent assignment`
`52`	`53`	`print( alwaysTrue && condition1 && condition2 );`

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