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chore: update lc problems: No.0263,No.0266,No.0267,No.0269,No.0274,No.0275 (doocs#1509)
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‎solution/0200-0299/0263.Ugly Number/README.md‎

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<pre>
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<strong>输入:</strong>n = 14
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<strong>输出:</strong>false
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<strong>解释:</strong>14 不是丑数,因为它包含了另外一个质因数&nbsp;<code>7 </code>。
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<strong>解释:</strong>14 不是丑数,因为它包含了另外一个质因数&nbsp;7 。
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</pre>
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<p>&nbsp;</p>

‎solution/0200-0299/0266.Palindrome Permutation/README.md‎

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<p><strong>示例 1:</strong></p>
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<pre><strong>输入:</strong> <code>&quot;code&quot;</code>
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<pre><strong>输入:</strong> &quot;code&quot;
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<strong>输出:</strong> false</pre>
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<p><strong>示例 2:</strong></p>
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<pre><strong>输入:</strong> <code>&quot;aab&quot;</code>
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<pre><strong>输入:</strong> &quot;aab&quot;
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<strong>输出:</strong> true</pre>
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<p><strong>示例 3:</strong></p>
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<pre><strong>输入:</strong> <code>&quot;carerac&quot;</code>
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<pre><strong>输入:</strong> &quot;carerac&quot;
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<strong>输出:</strong> true</pre>
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## 解法

‎solution/0200-0299/0267.Palindrome Permutation II/README.md‎

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<p><strong>示例 1:</strong></p>
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<pre>
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<strong>输入: </strong>s = <code>"aabb"</code>
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<strong>输出: </strong><code>["abba", "baab"]</code></pre>
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<strong>输入: </strong>s = "aabb"
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<strong>输出: </strong>["abba", "baab"]></pre>
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<p><strong>示例 2:</strong></p>
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<pre>
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<strong>输入: </strong>s = <code>"abc"</code>
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<strong>输出: </strong><code>[]</code>
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<strong>输入: </strong>s = "abc"
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<strong>输出: </strong>[]
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</pre>
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<p>&nbsp;</p>

‎solution/0200-0299/0269.Alien Dictionary/README.md‎

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<pre>
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<strong>输入:</strong>words = ["z","x","z"]
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<strong>输出:</strong>""
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<strong>解释:</strong>不存在合法字母顺序,因此返回 <code>"" 。</code>
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<strong>解释:</strong>不存在合法字母顺序,因此返回 "" 。
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</pre>
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<p>&nbsp;</p>

‎solution/0200-0299/0269.Alien Dictionary/README_EN.md‎

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<pre>
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<strong>Input:</strong> words = [&quot;z&quot;,&quot;x&quot;,&quot;z&quot;]
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<strong>Output:</strong> &quot;&quot;
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<strong>Explanation:</strong> The order is invalid, so return <code>&quot;&quot;</code>.
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<strong>Explanation:</strong> The order is invalid, so return &quot;&quot;.
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</pre>
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<p>&nbsp;</p>

‎solution/0200-0299/0274.H-Index/README.md‎

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<p><strong>示例 1:</strong></p>
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<pre>
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<strong>输入:</strong><code>citations = [3,0,6,1,5]</code>
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<strong>输入:</strong>citations = [3,0,6,1,5]
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<strong>输出:</strong>3
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<strong>解释:</strong>给定数组表示研究者总共有 <code>5</code> 篇论文,每篇论文相应的被引用了 <code>3, 0, 6, 1, 5</code> 次。
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&nbsp; 由于研究者有 <code>3 </code>篇论文每篇 <strong>至少 </strong>被引用了 <code>3</code> 次,其余两篇论文每篇被引用 <strong>不多于</strong> <code>3</code> 次,所以她的 <em>h </em>指数是 <code>3</code>。</pre>
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<strong>解释:</strong>给定数组表示研究者总共有 5 篇论文,每篇论文相应的被引用了 3, 0, 6, 1, 5 次。
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&nbsp; 由于研究者有 3 篇论文每篇 <strong>至少 </strong>被引用了 3 次,其余两篇论文每篇被引用 <strong>不多于</strong> 3 次,所以她的 <em>h </em>指数是 3。</pre>
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<p><strong>示例 2:</strong></p>
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‎solution/0200-0299/0275.H-Index II/README.md‎

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<p><strong class="example">示例 1:</strong></p>
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<pre>
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<strong>输入<code>:</code></strong><code>citations = [0,1,3,5,6]</code>
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<strong>输入:</strong>citations = [0,1,3,5,6]
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<strong>输出:</strong>3
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<strong>解释:</strong>给定数组表示研究者总共有 <code>5</code> 篇论文,每篇论文相应的被引用了 0<code>, 1, 3, 5, 6</code> 次。
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&nbsp; 由于研究者有 <code>3 </code>篇论文每篇<strong> 至少 </strong>被引用了 <code>3</code> 次,其余两篇论文每篇被引用<strong> 不多于</strong> <code>3</code> 次,所以她的<em> h </em>指数是 <code>3</code> 。</pre>
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<strong>解释:</strong>给定数组表示研究者总共有 5 篇论文,每篇论文相应的被引用了 0, 1, 3, 5, 6 次。
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&nbsp; 由于研究者有 3 篇论文每篇<strong> 至少 </strong>被引用了 3 次,其余两篇论文每篇被引用<strong> 不多于</strong> 3 次,所以她的<em> h </em>指数是 3 。</pre>
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<p><strong class="example">示例 2:</strong></p>
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‎solution/config.py‎

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