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Commit 94d498d

Browse files
feat: update solutions to lc problems (doocs#1788)
* No.0182.Duplicate Emails * No.1050.Actors and Directors Who Cooperated At Least Three Times * No.1495.Friendly Movies Streamed Last Month * No.1511.Customer Order Frequency * No.1587.Bank Account Summary II * No.1693.Daily Leads and Partners * No.1699.Number of Calls Between Two Persons * No.2562.Find the Array Concatenation Value
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‎.prettierignore‎

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/solution/0100-0199/0177.Nth Highest Salary/Solution.sql
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/solution/1400-1499/1454.Active Users/Solution.sql
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/solution/1400-1499/1484.Group Sold Products By The Date/Solution.sql
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/solution/1500-1599/1511.Customer Order Frequency/Solution.sql
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/solution/1600-1699/1613.Find the Missing IDs/Solution.sql
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/solution/1600-1699/1635.Hopper Company Queries I/Solution.sql
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/solution/1600-1699/1651.Hopper Company Queries III/Solution.sql

‎.prettierrc‎

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"solution/1400-1499/1445.Apples & Oranges/Solution.sql",
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"solution/1400-1499/1479.Sales by Day of the Week/Solution.sql",
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"solution/1500-1599/1501.Countries You Can Safely Invest In/Solution.sql",
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"solution/1500-1599/1511.Customer Order Frequency/Solution.sql",
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"solution/1500-1599/1555.Bank Account Summary/Solution.sql",
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"solution/1600-1699/1667.Fix Names in a Table/Solution.sql",
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"solution/1600-1699/1699.Number of Calls Between Two Persons/Solution.sql",
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"solution/1700-1799/1777.Product's Price for Each Store/Solution.sql",
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"solution/1900-1999/1934.Confirmation Rate/Solution.sql",
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"solution/1900-1999/1972.First and Last Call On the Same Day/Solution.sql",

‎solution/0100-0199/0182.Duplicate Emails/README.md‎

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<!-- 这里可写通用的实现逻辑 -->
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**方法一:分组统计**
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我们可以使用 `GROUP BY` 语句,按照 `email` 字段进行分组,然后使用 `HAVING` 语句,筛选出现次数大于 1ドル$ 的 `email`。
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**方法二:自连接**
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我们可以使用自连接的方法,将 `Person` 表自身连接一次,然后筛选出 `id` 不同,但 `email` 相同的记录。
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<!-- tabs:start -->
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### **SQL**
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```sql
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SELECT Email
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# Write your MySQL query statement below
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SELECT email
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FROM Person
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GROUP BY Email
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HAVING count(Email) > 1;
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GROUP BY 1
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HAVING count(1) > 1;
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```
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```sql

‎solution/0100-0199/0182.Duplicate Emails/README_EN.md‎

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## Solutions
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**Solution 1: Group By + Having**
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We can use the `GROUP BY` statement to group the data by the `email` field, and then use the `HAVING` statement to filter out the `email` addresses that appear more than once.
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**Solution 2: Self-Join**
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We can use a self-join to join the `Person` table with itself, and then filter out the records where the `id` is different but the `email` is the same.
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<!-- tabs:start -->
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### **SQL**
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```sql
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SELECT Email
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# Write your MySQL query statement below
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SELECT email
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FROM Person
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GROUP BY Email
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HAVING count(Email) > 1;
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GROUP BY 1
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HAVING count(1) > 1;
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```
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```sql
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SELECT Email
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# Write your MySQL query statement below
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SELECT email
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FROM Person
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GROUP BY Email
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HAVING count(Email) > 1;
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GROUP BY 1
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HAVING count(1) > 1;

‎solution/1000-1099/1050.Actors and Directors Who Cooperated At Least Three Times/README.md‎

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<!-- 这里可写通用的实现逻辑 -->
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**方法一:使用 `GROUP BY` + `HAVING`**
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**方法一:分组统计**
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我们将 `ActorDirector` 表按照 `actor_id` 和 `director_id` 进行分组,然后使用 `HAVING` 过滤出合作次数大于等于 3ドル$ 次的组。
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我们可以使用 `GROUP BY` 语句,按照 `actor_id` 和 `director_id` 字段进行分组,然后使用 `HAVING` 语句,筛选出现次数大于等于 3ドル$ 的 `actor_id` 和 `director_id`。
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<!-- tabs:start -->
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‎solution/1000-1099/1050.Actors and Directors Who Cooperated At Least Three Times/README_EN.md‎

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## Solutions
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Use `GROUP BY` & `HAVING`.
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**Solution 1: Group By + Having**
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We can use the `GROUP BY` statement to group the data by the `actor_id` and `director_id` fields, and then use the `HAVING` statement to filter out the `actor_id` and `director_id` that appear at least three times.
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<!-- tabs:start -->
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‎solution/1400-1499/1495.Friendly Movies Streamed Last Month/README.md‎

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<!-- 这里可写通用的实现逻辑 -->
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**方法一:等值连接 + 条件筛选**
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我们可以先通过等值连接将两张表按照 `content_id` 字段连接起来,然后再通过条件筛选出在 2020ドル$ 年 6ドル$ 月份播放的儿童适宜电影。
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### **SQL**
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```sql
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SELECT DISTINCT
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title
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# Write your MySQL query statement below
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SELECT DISTINCT title
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FROM
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Content
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INNER JOIN TVProgram ONContent.content_id=TVProgram.content_id
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TVProgram
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JOIN Content USING (content_id)
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WHERE
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content_type = 'Movies'
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date_format(program_date, '%Y%m') = '202006'
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AND kids_content = 'Y'
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AND program_date BETWEEN '2020年06月01日' AND '2020年06月30日';
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```
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```sql
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SELECT DISTINCT
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title
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FROM
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Content
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INNER JOIN TVProgram ON Content.content_id = TVProgram.content_id
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WHERE kids_content = 'Y' AND (MONTH(program_date), YEAR(program_date)) = (6, 2020);
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AND content_type = 'Movies';
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```
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<!-- tabs:end -->

‎solution/1400-1499/1495.Friendly Movies Streamed Last Month/README_EN.md‎

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## Solutions
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**Solution 1: Equi-Join + Conditional Filtering**
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We can first use an equi-join to join the two tables based on the `content_id` field, and then use conditional filtering to select the child-friendly movies that were played in June 2020.
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```sql
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SELECT DISTINCT
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title
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# Write your MySQL query statement below
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SELECT DISTINCT title
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FROM
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Content
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INNER JOIN TVProgram ONContent.content_id=TVProgram.content_id
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TVProgram
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JOIN Content USING (content_id)
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WHERE
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content_type = 'Movies'
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date_format(program_date, '%Y%m') = '202006'
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AND kids_content = 'Y'
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AND program_date BETWEEN '2020年06月01日' AND '2020年06月30日';
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```
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```sql
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SELECT DISTINCT
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title
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FROM
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Content
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INNER JOIN TVProgram ON Content.content_id = TVProgram.content_id
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WHERE kids_content = 'Y' AND (MONTH(program_date), YEAR(program_date)) = (6, 2020);
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AND content_type = 'Movies';
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```
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<!-- tabs:end -->
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SELECT DISTINCT
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title
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# Write your MySQL query statement below
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SELECT DISTINCT title
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FROM
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Content
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INNER JOIN TVProgram ONContent.content_id=TVProgram.content_id
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TVProgram
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JOIN Content USING (content_id)
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WHERE
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content_type = 'Movies'
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date_format(program_date, '%Y%m') = '202006'
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AND kids_content = 'Y'
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AND program_date BETWEEN '2020年06月01日' AND '2020年06月30日';
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SELECT DISTINCT
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title
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FROM
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Content
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INNER JOIN TVProgram ON Content.content_id = TVProgram.content_id
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WHERE kids_content = 'Y' AND (MONTH(program_date), YEAR(program_date)) = (6, 2020);
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AND content_type = 'Movies';

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