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50 | 50 |
|
51 | 51 | <!-- 这里可写通用的实现逻辑 -->
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52 | 52 |
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| 53 | +```bash |
| 54 | + i-2 |
| 55 | + case 1 : i-1┌─┐ |
| 56 | + └─┼─>i |
| 57 | + i-3 |
| 58 | + |
| 59 | + i-2 |
| 60 | + case 2 : i-1 ┌────┐ |
| 61 | + └─══>┘i-3 |
| 62 | + i i-4 |
| 63 | + |
| 64 | + case 3 : i-4 |
| 65 | + ┌──┐ |
| 66 | + │i<┼─┐ |
| 67 | + i-3│ i-5│i-1 |
| 68 | + └────┘ |
| 69 | + i-2 |
| 70 | +``` |
| 71 | + |
53 | 72 | <!-- tabs:start -->
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54 | 73 |
|
55 | 74 | ### **Python3**
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56 | 75 |
|
57 | 76 | <!-- 这里可写当前语言的特殊实现逻辑 -->
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58 | 77 |
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59 | 78 | ```python
|
60 | | - |
| 79 | +class Solution: |
| 80 | + def isSelfCrossing(self, distance: List[int]) -> bool: |
| 81 | + d = distance |
| 82 | + for i in range(3, len(d)): |
| 83 | + if d[i] >= d[i - 2] and d[i - 1] <= d[i - 3]: |
| 84 | + return True |
| 85 | + if i >= 4 and d[i - 1] == d[i - 3] and d[i] + d[i - 4] >= d[i - 2]: |
| 86 | + return True |
| 87 | + if i >= 5 and d[i - 2] >= d[i - 4] and d[i - 1] <= d[i - 3] and d[i] >= d[i - 2] - d[i - 4] and d[i - 1] + d[i - 5] >= d[i - 3]: |
| 88 | + return True |
| 89 | + return False |
61 | 90 | ```
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62 | 91 |
|
63 | 92 | ### **Java**
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64 | 93 |
|
65 | 94 | <!-- 这里可写当前语言的特殊实现逻辑 -->
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66 | 95 |
|
67 | 96 | ```java
|
| 97 | +class Solution { |
| 98 | + public boolean isSelfCrossing(int[] distance) { |
| 99 | + int[] d = distance; |
| 100 | + for (int i = 3; i < d.length; ++i) { |
| 101 | + if (d[i] >= d[i - 2] && d[i - 1] <= d[i - 3]) { |
| 102 | + return true; |
| 103 | + } |
| 104 | + if (i >= 4 && d[i - 1] == d[i - 3] && d[i] + d[i - 4] >= d[i - 2]) { |
| 105 | + return true; |
| 106 | + } |
| 107 | + if (i >= 5 && d[i - 2] >= d[i - 4] && d[i - 1] <= d[i - 3] && d[i] >= d[i - 2] - d[i - 4] && d[i - 1] + d[i - 5] >= d[i - 3]) { |
| 108 | + return true; |
| 109 | + } |
| 110 | + } |
| 111 | + return false; |
| 112 | + } |
| 113 | +} |
| 114 | +``` |
| 115 | + |
| 116 | +### **C++** |
| 117 | + |
| 118 | +```cpp |
| 119 | +class Solution { |
| 120 | +public: |
| 121 | + bool isSelfCrossing(vector<int>& distance) { |
| 122 | + vector<int> d = distance; |
| 123 | + for (int i = 3; i < d.size(); ++i) |
| 124 | + { |
| 125 | + if (d[i] >= d[i - 2] && d[i - 1] <= d[i - 3]) return true; |
| 126 | + if (i >= 4 && d[i - 1] == d[i - 3] && d[i] + d[i - 4] >= d[i - 2]) return true; |
| 127 | + if (i >= 5 && d[i - 2] >= d[i - 4] && d[i - 1] <= d[i - 3] && d[i] >= d[i - 2] - d[i - 4] && d[i - 1] + d[i - 5] >= d[i - 3]) return true; |
| 128 | + } |
| 129 | + return false; |
| 130 | + } |
| 131 | +}; |
| 132 | +``` |
68 | 133 |
|
| 134 | +### **Go** |
| 135 | + |
| 136 | +```go |
| 137 | +func isSelfCrossing(distance []int) bool { |
| 138 | + d := distance |
| 139 | + for i := 3; i < len(d); i++ { |
| 140 | + if d[i] >= d[i-2] && d[i-1] <= d[i-3] { |
| 141 | + return true |
| 142 | + } |
| 143 | + if i >= 4 && d[i-1] == d[i-3] && d[i]+d[i-4] >= d[i-2] { |
| 144 | + return true |
| 145 | + } |
| 146 | + if i >= 5 && d[i-2] >= d[i-4] && d[i-1] <= d[i-3] && d[i] >= d[i-2]-d[i-4] && d[i-1]+d[i-5] >= d[i-3] { |
| 147 | + return true |
| 148 | + } |
| 149 | + } |
| 150 | + return false |
| 151 | +} |
69 | 152 | ```
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70 | 153 |
|
71 | 154 | ### **...**
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