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40 | 40 |
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41 | 41 | <!-- 这里可写通用的实现逻辑 -->
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42 | 42 |
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| 43 | +前缀和加哈希表,把 0 当作 -1 处理,题目变成求和为 0 的子数组 |
| 44 | + |
43 | 45 | <!-- tabs:start -->
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44 | 46 |
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45 | 47 | ### **Python3**
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46 | 48 |
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47 | 49 | <!-- 这里可写当前语言的特殊实现逻辑 -->
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48 | 50 |
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49 | 51 | ```python
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50 | | - |
| 52 | +class Solution: |
| 53 | + def findMaxLength(self, nums: List[int]) -> int: |
| 54 | + m = {0: -1} |
| 55 | + ans, sum = 0, 0 |
| 56 | + for i, num in enumerate(nums): |
| 57 | + sum += 1 if num == 1 else -1 |
| 58 | + if sum in m: |
| 59 | + ans = max(ans, i - m[sum]) |
| 60 | + else: |
| 61 | + m[sum] = i |
| 62 | + return ans |
51 | 63 | ```
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52 | 64 |
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53 | 65 | ### **Java**
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54 | 66 |
|
55 | 67 | <!-- 这里可写当前语言的特殊实现逻辑 -->
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56 | 68 |
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57 | 69 | ```java
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| 70 | +class Solution { |
| 71 | + public int findMaxLength(int[] nums) { |
| 72 | + Map<Integer, Integer> m = new HashMap<>(); |
| 73 | + m.put(0, -1); |
| 74 | + int ans = 0, sum = 0; |
| 75 | + for (int i = 0; i < nums.length; i++) { |
| 76 | + sum += nums[i] == 1 ? 1 : -1; |
| 77 | + if (m.containsKey(sum)) { |
| 78 | + ans = Math.max(ans, i - m.get(sum)); |
| 79 | + } else { |
| 80 | + m.put(sum, i); |
| 81 | + } |
| 82 | + } |
| 83 | + return ans; |
| 84 | + } |
| 85 | +} |
| 86 | +``` |
58 | 87 |
|
| 88 | +### **Go** |
| 89 | + |
| 90 | +```go |
| 91 | +func findMaxLength(nums []int) int { |
| 92 | + m := map[int]int{0: -1} |
| 93 | + ans, sum := 0, 0 |
| 94 | + for i, num := range nums { |
| 95 | + if num == 0 { |
| 96 | + sum -= 1 |
| 97 | + } else { |
| 98 | + sum += 1 |
| 99 | + } |
| 100 | + if j, ok := m[sum]; ok { |
| 101 | + ans = max(ans, i-j) |
| 102 | + } else { |
| 103 | + m[sum] = i |
| 104 | + } |
| 105 | + } |
| 106 | + return ans |
| 107 | +} |
| 108 | + |
| 109 | +func max(a, b int) int { |
| 110 | + if a > b { |
| 111 | + return a |
| 112 | + } |
| 113 | + return b |
| 114 | +} |
59 | 115 | ```
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60 | 116 |
|
61 | 117 | ### **...**
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