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Commit 74f8ed2

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feat: update solutions to lc problem: No.2310
No.2310.Sum of Numbers With Units Digit K
1 parent 5982173 commit 74f8ed2

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‎solution/2300-2399/2310.Sum of Numbers With Units Digit K/README.md‎

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我们从小到达枚举 $n,ドル找到第一个满足 $num-n*k$ 是 10ドル$ 的倍数的 $n$。由于 $n$ 不会超过 $num,ドル因此 $n$ 最大枚举至 $num$。
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也可以只考虑个位,个位满足,高位随意。
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**方法二:记忆化搜索**
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<!-- tabs:start -->
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return -1
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```
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```python
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class Solution:
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def minimumNumbers(self, num: int, k: int) -> int:
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if num == 0:
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return 0
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for i in range(1, 11):
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if (k * i) % 10 == num % 10 and k * i <= num:
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return i
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return -1
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```
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```python
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class Solution:
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def minimumNumbers(self, num: int, k: int) -> int:
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}
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```
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```java
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class Solution {
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public int minimumNumbers(int num, int k) {
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if (num == 0) {
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return 0;
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}
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for (int i = 1; i <= 10; ++i) {
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if ((k * i) % 10 == num % 10 && k * i <= num) {
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return i;
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}
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}
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return -1;
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}
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}
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```
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### **C++**
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```cpp
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};
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```
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```cpp
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class Solution {
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public:
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int minimumNumbers(int num, int k) {
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if (!num) return 0;
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for (int i = 1; i <= 10; ++i)
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if ((k * i) % 10 == num % 10 && k * i <= num)
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return i;
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return -1;
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}
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};
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```
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### **Go**
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```go
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}
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```
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```go
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func minimumNumbers(num int, k int) int {
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if num == 0 {
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return 0
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}
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for i := 1; i <= 10; i++ {
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if (k*i)%10 == num%10 && k*i <= num {
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return i
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}
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}
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return -1
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}
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```
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### **TypeScript**
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```ts

‎solution/2300-2399/2310.Sum of Numbers With Units Digit K/README_EN.md‎

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return -1
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```
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```python
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class Solution:
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def minimumNumbers(self, num: int, k: int) -> int:
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if num == 0:
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return 0
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for i in range(1, 11):
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if (k * i) % 10 == num % 10 and k * i <= num:
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return i
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return -1
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```
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```python
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class Solution:
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def minimumNumbers(self, num: int, k: int) -> int:
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}
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```
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```java
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class Solution {
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public int minimumNumbers(int num, int k) {
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if (num == 0) {
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return 0;
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}
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for (int i = 1; i <= 10; ++i) {
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if ((k * i) % 10 == num % 10 && k * i <= num) {
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return i;
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}
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}
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return -1;
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}
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}
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```
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### **C++**
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```cpp
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};
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```
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```cpp
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class Solution {
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public:
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int minimumNumbers(int num, int k) {
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if (!num) return 0;
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for (int i = 1; i <= 10; ++i)
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if ((k * i) % 10 == num % 10 && k * i <= num)
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return i;
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return -1;
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}
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};
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```
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### **Go**
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```go
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}
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```
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```go
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func minimumNumbers(num int, k int) int {
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if num == 0 {
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return 0
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}
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for i := 1; i <= 10; i++ {
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if (k*i)%10 == num%10 && k*i <= num {
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return i
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}
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}
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return -1
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}
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```
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### **TypeScript**
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```ts

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