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Add versions of DigitCount & DigitSum that work for all bases #17

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completedIssue completed and committed to develop. To be closed on next release enhancementNew feature or request
@delphidabbler

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If n ∈ N (n ≠ 0) and b is the number base (b>1) then the number of digits, d, of n is

d = ⌊logb(n)⌋ + 1

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completedIssue completed and committed to develop. To be closed on next release enhancementNew feature or request

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