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Commit 5fc33c0

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Add a recursive version of the Longest Common Subsequence.
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import longestCommonSubsequence from '../longestCommonSubsequenceRecursive';
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describe('longestCommonSubsequenceRecursive', () => {
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it('should find longest common substring between two strings', () => {
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expect(longestCommonSubsequence('', '')).toBe('');
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expect(longestCommonSubsequence('ABC', '')).toBe('');
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expect(longestCommonSubsequence('', 'ABC')).toBe('');
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expect(longestCommonSubsequence('ABABC', 'BABCA')).toBe('BABC');
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expect(longestCommonSubsequence('BABCA', 'ABCBA')).toBe('ABCA');
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expect(longestCommonSubsequence('sea', 'eat')).toBe('ea');
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expect(longestCommonSubsequence('algorithms', 'rithm')).toBe('rithm');
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expect(longestCommonSubsequence(
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'Algorithms and data structures implemented in JavaScript',
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'Here you may find Algorithms and data structures that are implemented in JavaScript',
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)).toBe('Algorithms and data structures implemented in JavaScript');
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});
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});

‎src/algorithms/string/longest-common-substring/longestCommonSubstringRecursive.js renamed to ‎src/algorithms/sets/longest-common-subsequence/longestCommonSubsequenceRecursive.js

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/* eslint-disable no-param-reassign */
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/**
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* Longest Common Substring (LCS) (Recursive Approach).
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* Longest Common Subsequence (LCS) (Recursive Approach).
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*
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* @param {string} string1
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* @param {string} string2
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* @return {number}
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*/
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export default function longestCommonSubstringRecursive(string1, string2) {
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export default function longestCommonSubsequenceRecursive(string1, string2) {
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/**
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*
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* @param {string} s1
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* @param {string} s2
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* @return {string} - returns the LCS (Longest Common Substring)
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* @return {string} - returns the LCS (Longest Common Subsequence)
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*/
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const lcs = (s1, s2, memo = {}) => {
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if (!s1 || !s2) return '';

‎src/algorithms/string/longest-common-substring/__test__/longestCommonSubstringRecursive.test.js

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