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Commit 715afa8

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inversions_in_array
finding the number of inversions in an array using merge sort(O(nlogn)) as well as intuitive solution(O(n^2))
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‎04-Sorting/inversions.cpp

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#include "bits/stdc++.h"
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using namespace std;
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void printArr(int arr[], int n,string s="\n"){
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if(s==" "){
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for(int i=0;i<n;i++){
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cout<<arr[i]<<" ";
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}
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cout<<endl;
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}
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else{
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for(int i=0;i<n;i++){
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cout<<arr[i]<<'\n';
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}
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}
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}
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int merge(int left[], int right[], int arr[], int leftLength, int rightLength){
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int i=0,j=0,k = 0;
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int inversions = 0 ;
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while(i< leftLength && j<rightLength){
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if(left[i]<=right[j]){
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arr[k]= left[i];
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i++;
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k++;
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}
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else {
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arr[k] = right[j];
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j++;
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k++;
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inversions += leftLength - i;
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}
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}
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while(i<leftLength){
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arr[k] = left[i];
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i++;
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k++;
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//inversions += rightLength;
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}
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while(j<rightLength){
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arr[k] = right[j];
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j++;
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k++;
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}
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return inversions;
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}
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int mergeSort(int arr[], int n){
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int mid = n/2;
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if(n<2){
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return 0;
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}
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int left[mid];
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int right[n-mid];
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for(int i = 0 ; i<mid;i++){
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left[i] = arr[i];
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}
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//printArr(left, mid," ");
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int i = 0 ;
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for(int j = mid;j<n;j++){
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right[i] = arr[j];
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i++;
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}
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//printArr(right, n-mid," ");
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int x = mergeSort(left, mid);
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int y = mergeSort(right, n- mid);
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int z = merge(left, right, arr,mid, n- mid);
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return x+y+z;
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}
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int inversions(int arr[], int n){
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int d = 0;
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for(int i = 0 ;i< n;i++){
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for(int j = i+1;j<n;j++){
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if(arr[i]>arr[j]){
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d++;
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}
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}
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}
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return d;}
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int main(){
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int arr[8] = {2,1,4,6,7,5,3,8};
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cout<< "Inversions are:"<< inversions(arr,8)<<endl;
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cout<< "Inversions output:"<< mergeSort(arr,8)<<endl;
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return 0;
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}

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