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fea: 2 / 이진 변환 반복하기 / 새로운 문제

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	`1`	`+//https://github.com/codeisneverodd/programmers-coding-test`
	`2`	`+//더 좋은 풀이가 존재할 수 있습니다.`
	`3`	`+//정답 1 - codeisneverodd`
	`4`	`+function solution(s) {`
	`5`	`+ const removeZero = s => {`
	`6`	`+ const removed = s`
	`7`	`+ .split('')`
	`8`	`+ .filter(n => n !== '0')`
	`9`	`+ .join('');`
	`10`	`+ return { removed, count: s.length - removed.length };`
	`11`	`+ };`
	`12`	`+`
	`13`	`+ const convertToBinary = (s, turnCount, removedCount) => {`
	`14`	`+ if (s === '1') return [turnCount, removedCount];`
	`15`	`+ const { removed, count } = removeZero(s);`
	`16`	`+ return convertToBinary(removed.length.toString(2), turnCount + 1, removedCount + count);`
	`17`	`+ };`
	`18`	`+`
	`19`	`+ return convertToBinary(s, 0, 0);`
	`20`	`+}`

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