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Commit bf5e444

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Adding Solutions
1 parent 99df532 commit bf5e444

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‎README.md

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# Leetcode SQL Questions & Solutions <br/>
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#### Repository Contains :<br/>
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(1) 160+ Leetcode SQL Question Solutions<br/>
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(1) 190+ Leetcode SQL Question Solutions<br/>
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(2) PostgreSQL Dump File (leetcodedb.sql)<br/>
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#### Problem statements of all questions including leetcode premium questions :<br/>

‎dump_file/leetcodedb.sql

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SELECT v.customer_id,COUNT(v.visit_id)
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FROM visits_1581 v
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LEFT JOIN transactions_1581 t ON v.visit_id = t.visit_id
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WHERE t.transaction_id IS NULL
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GROUP BY v.customer_id
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ORDER BY v.customer_id;
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SELECT u.name,SUM(t.amount)
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FROM transactions_1587 t
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INNER JOIN users_1587 u ON t.account=u.account
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GROUP BY u.name
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HAVING SUM(t.amount) > 10000
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SELECT seller_name
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FROM seller_1607
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WHERE seller_id NOT IN
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(SELECT DISTINCT seller_id
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FROM orders_1607
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WHERE EXTRACT(YEAR FROM sale_date) = 2020);
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SELECT a.student_name,b.student_name,c.student_name
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FROM school_a_1623 a
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CROSS JOIN school_b_1623 b
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CROSS JOIN school_c_1623 c
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WHERE a.student_id <> b.student_id AND a.student_id <> c.student_id AND b.student_id <> c.student_id AND
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a.student_name <> b.student_name AND a.student_name <> c.student_name AND b.student_name <> c.student_name;
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SELECT contest_id,ROUND((COUNT(DISTINCT user_id)*100.0)/user_count.cnt,2) AS percentage
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FROM register_1633
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CROSS JOIN (SELECT COUNT(*) AS cnt FROM users_1633) user_count
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GROUP BY contest_id,user_count.cnt
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ORDER BY percentage DESC,contest_id;
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--OR--
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SELECT contest_id,ROUND((COUNT(DISTINCT user_id)*100.0)/(SELECT COUNT(*) AS cnt FROM users_1633),2) AS percentage
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FROM register_1633
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GROUP BY contest_id
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ORDER BY percentage DESC,contest_id;
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SELECT s.machine_id,ROUND(AVG(e.timestamp-s.timestamp)::NUMERIC,3) AS processing_time
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FROM activity_1661 s
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INNER JOIN activity_1661 e
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ON s.activity_type = 'start' AND e.activity_type = 'end' AND
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s.machine_id = e.machine_id AND s.process_id = e.process_id
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GROUP BY s.machine_id;
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SELECT user_id,INITCAP(name)
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FROM users_1667
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ORDER BY user_id;
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SELECT p.name,SUM(i.rest) AS rest,SUM(i.paid) AS paid,SUM(i.canceled) AS canceled,SUM(i.refunded) AS refunded
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FROM invoice_1677 i
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INNER JOIN product_1677 p ON i.product_id = p.product_id
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GROUP BY p.name
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ORDER BY p.name;

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