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Commit affd056

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author
Shuo
authored
Merge pull request #316 from openset/develop
Add: Winning Candidate
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‎problems/winning-candidate/README.md‎

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## 574. Winning Candidate
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<!--|This file generated by command(leetcode description); DO NOT EDIT. |-->
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<!--+----------------------------------------------------------------------+-->
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<!--|@author Openset <openset.wang@gmail.com> |-->
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<!--|@link https://github.com/openset |-->
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<!--|@home https://github.com/openset/leetcode |-->
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<!--+----------------------------------------------------------------------+-->
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## 574. Winning Candidate (Medium)
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<p>Table: <code>Candidate</code></p>
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<pre>
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+-----+---------+
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| id | Name |
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+-----+---------+
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| 1 | A |
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| 2 | B |
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| 3 | C |
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| 4 | D |
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| 5 | E |
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+-----+---------+
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</pre>
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<p>Table: <code>Vote</code></p>
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<pre>
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+-----+--------------+
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| id | CandidateId |
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+-----+--------------+
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| 1 | 2 |
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| 2 | 4 |
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| 3 | 3 |
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| 4 | 2 |
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| 5 | 5 |
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+-----+--------------+
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id is the auto-increment primary key,
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CandidateId is the id appeared in Candidate table.
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</pre>
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<p>Write a sql to find the name of the winning candidate, the above example will return the winner <code>B</code>.</p>
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<pre>
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+------+
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| Name |
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+------+
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| B |
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+------+
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</pre>
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<p><b>Notes:</b><br />
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<ol>
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<li>You may assume <b>there is no tie</b>, in other words there will be <b>at most one</b> winning candidate.</li>
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</ol></p>

‎problems/winning-candidate/winning_candidate.go‎

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# Write your MySQL query statement below
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SELECT `name` AS 'Name'
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FROM
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Candidate
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JOIN (
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SELECT Candidateid
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FROM
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Vote
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GROUP BY
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Candidateid
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ORDER BY
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COUNT(*) DESC
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LIMIT 1
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) AS winner
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WHERE
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Candidate.id = winner.Candidateid;

‎problems/winning-candidate/winning_candidate_test.go‎

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