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Commit 4e3aa2e

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Grouping Aggregate Results (GROUP BY)
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‎data/10-more-queries.sql‎

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@@ -2,3 +2,7 @@ SELECT * FROM users
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WHERE first_name LIKE 'Ma%';
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SELECT COUNT(id) FROM locations;
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SELECT c.name, loc.street, COUNT(loc.id) AS num_locations FROM cities AS c
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LEFT JOIN locations AS loc ON loc.city_name = c.name
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GROUP BY c.name, loc.street;

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