diff --git a/Dynamic-Programming/BestTimetoBuyandSellStock.js b/Dynamic-Programming/BestTimetoBuyandSellStock.js
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+/*
+ Author : Neha611 
+ github Link:https://github.com/Neha611
+ 
+ Problem Description:
+ You are given an array prices where prices[i] is the price of a given stock on the ith day.
+ You want to maximize your profit by choosing a single day to buy one stock and choosing a different day in the future to sell that stock.
+ Return the maximum profit you can achieve from this transaction. If you cannot achieve any profit, return 0.
+
+ Example:
+ Input: prices = [7,1,5,3,6,4]
+ Output: 5
+ Explanation: Buy on day 2 (price = 1) and sell on day 5 (price = 6), profit = 6-1 = 5.
+ Note that buying on day 2 and selling on day 1 is not allowed because you must buy before you sell.
+
+ Problem Link:
+ https://leetcode.com/problems/best-time-to-buy-and-sell-stock/description/
+*/
+
+/**
+ * @param {number[]} prices
+ * @return {number}
+ */
+var maxProfit = function(prices) {
+ let buy_day=-1;
+ let buy=Number.MAX_VALUE;
+ let sell_day=-1;
+ let profit=0;
+ for(let i=0;i<prices.length;i++) + { + if(prices[i]<buy) + { + /*we will buy the stock with lower price*/ + buy=prices[i]; + buy_day=i; + } + else if(prices[i]>prices[buy_day])
+ {
+ /*if the current price of stock is higher than the price it is bought with we can or cannot sell on this day*/
+ sell_day=i;
+ }
+ if(buy_day<sell_day)
+ {
+ /*get profit*/
+ profit=Math.max(profit,prices[sell_day]-prices[buy_day]);
+ }
+ }
+ return profit;
+};
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