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Commit 7121a6d

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Project Euler : fix solution for problem 20 (Factorial digit sum).
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‎Project-Euler/Problem020.js‎

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/*
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Factorial digit sum
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/**
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* Problem 20 - Factorial digit sum
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*
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* @see {@link https://projecteuler.net/problem=20}
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*
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* n! means n ×ばつ (n − 1) ×ばつ ... ×ばつ 3 ×ばつ 2 ×ばつ 1
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*
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* For example, 10! = 10 ×ばつ 9 ×ばつ ... ×ばつ 3 ×ばつかける 2 ×ばつかける 1 = 3628800,
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* and the sum of the digits in the number 10! is 3 +たす 6 +たす 2 +たす 8 +たす 8 +たす 0 +たす 0 = 27
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*
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* Find the sum of the digits in the number 100!
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*/
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n! means n ×ばつ (n − 1) ×ばつ ... ×ばつ 3 ×ばつ 2 ×ばつ 1
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constfactorialDigitSum=function (n =100){
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For example, 10! = 10 ×ばつ 9 ×ばつ ... ×ばつ 3 ×ばつかける 2 ×ばつかける 1 = 3628800,
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and the sum of the digits in the number 10! is 3 +たす 6 +たす 2 +たす 8 +たす 8 +たす 0 +たす 0 = 27.
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// Consider each digit*10^exp separately, right-to-left ([units, tens, ...]).
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letdigits =[1];
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Find the sum of the digits in the number 100!
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*/
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for (let x=2; x<=n; x++) {
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let carry = 0;
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for (let exp=0; exp<digits.length; exp++) {
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const prod = digits[exp]*x + carry;
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carry = Math.floor(prod/10);
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digits[exp] = prod % 10;
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}
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while (carry > 0) {
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digits.push(carry%10);
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carry = Math.floor(carry/10);
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}
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}
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const findFactorialDigitSum = (num) => {
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let result = 0
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const stringifiedNumber = factorize(num).toLocaleString('fullwide', { useGrouping: false })
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stringifiedNumber.split('').map(num => { result += Number(num) })
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return result
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// (digits are reversed but we only want the sum so it doesn't matter)
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return digits.reduce((prev, current) => prev + current, 0)
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}
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constfactorize=(num)=>num===0 ? 1 : num*factorize(num-1)
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console.log('Factorial digit sum of 100! :',factorialDigitSum())
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console.log(findFactorialDigitSum(100))
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module.exports=factorialDigitSum

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