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Commit f8619c8

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Generalized Abbreviation
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'''Leetcode- https://leetcode.com/problems/generalized-abbreviation/ '''
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'''
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A word's generalized abbreviation can be constructed by taking any number of non-overlapping and non-adjacent substrings and replacing them with their respective lengths.
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For example, "abcde" can be abbreviated into:
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"a3e" ("bcd" turned into "3")
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"1bcd1" ("a" and "e" both turned into "1")
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"5" ("abcde" turned into "5")
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"abcde" (no substrings replaced)
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However, these abbreviations are invalid:
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"23" ("ab" turned into "2" and "cde" turned into "3") is invalid as the substrings chosen are adjacent.
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"22de" ("ab" turned into "2" and "bc" turned into "2") is invalid as the substring chosen overlap.
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Given a string word, return a list of all the possible generalized abbreviations of word. Return the answer in any order.
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Example 1:
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Input: word = "word"
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Output: ["4","3d","2r1","2rd","1o2","1o1d","1or1","1ord","w3","w2d","w1r1","w1rd","wo2","wo1d","wor1","word"]
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'''
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def generateAbbreviations(word):
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res = []
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def backtrack(i,cur):
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if i == len(word):
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res.append("".join(cur))
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return
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cur.append(word[i])
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backtrack(i+1,cur)
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cur.pop()
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if not cur or not cur[-1][-1].isdigit():
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for j in range(1,len(word)-i+1):
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cur.append(str(j))
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backtrack(i+j,cur)
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cur.pop()
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backtrack(0,[])
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return res
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#T: O(n.2^n)
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#S:O(n)

‎README.md

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- [x] [Generate Parentheses](Backtracking/22-Generate-Parentheses.py)
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- [x] [Palindrome Partitioning](Backtracking/131-Palindrome-Partitioning.py)
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- [x] [Letter Combinations of a Phone Number](Backtracking/17-Letter-Combinations-of-a-Phone-Number.py)
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- [x] [Generalized Abbreviation](Backtracking/320-Generalized-Abbreviation.py)
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