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Commit bf86b7c

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polishing v1
1 parent 2b1d62e commit bf86b7c

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‎Harder/Generate-Sentences.md

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Damn easy, isn't it?
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[![Next Page](assets/next-button.png)](..README.md)
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###### tags: `programmig-hero` `python` `float` `int` `math`

‎Harder/Password-generator.md

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The solution is rather simple. We imported the random module and the string module. Then we created a long string by joining all ascii_letters, digits and special characters.
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For that, we ran a for loop. In the loop, we select a random letter from the all_chars. To select a random character, we used random.choice. Then we add the random character to the password.
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[![Next Page](assets/next-button.png)](Password-with-requirements.md)
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###### tags: `programmig-hero` `python` `float` `int` `math`

‎Harder/Password-with-requirements.md

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Keep going. Only a few more left. I am sure you can do it
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[![Next Page](assets/next-button.png)](Permutations.md)
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###### tags: `programmig-hero` `python` `float` `int` `math`

‎Harder/Permutations.md

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This will create [3, 2, 1]. That’s why we did [current] + p to make the final permutation.
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This code is harder. It will take a few practices to become comfortable with it.
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This code is harder. It will take a few practices to become comfortable with it.
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[![Next Page](assets/next-button.png)](Generate-Sentences.md)
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###### tags: `programmig-hero` `python` `float` `int` `math`

‎Harder/Simple-Calculator.md

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That’s it.
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[![Next Page](assets/next-button.png)](Password-generator.md)
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###### tags: `programmig-hero` `python` `float` `int` `math`

‎Medium/Armstrong-number.md

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```
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###### tags: `programmig-hero` `python` `float` `int` `math`
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‎Medium/Check-palindrome.md

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So, the more you explore, the more you try, the more shortcut trick you will master.
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[![Next Page](../assets/next-button.png)](Dictionary-of-cubes.md)
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###### tags: `programmig-hero` `python` `float` `int` `math`
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‎Medium/Dictionary-of-cubes.md

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## Take Away
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Sum of a series might have an easier formula.
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###### tags: `programmig-hero` `python` `float` `int` `math`
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‎Medium/Greatest-common-divisor.md

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gcd = math.gcd(a,b)
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print(gcd)
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```
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```
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###### tags: `programmig-hero` `python` `float` `int` `math`
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‎Medium/Least-Common-Multiple.md

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That's it.
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It's actually much easier than it seems.
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[![Next Page](../assets/next-button.png)](README.md)
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###### tags: `programmig-hero` `python` `float` `int` `math`
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