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Commit e0b8f0c

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added daily challenge
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‎543. Diameter of Binary Tree.py‎

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# Definition for a binary tree node.
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# class TreeNode:
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# def __init__(self, val=0, left=None, right=None):
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# self.val = val
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# self.left = left
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# self.right = right
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class Solution:
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def diameterOfBinaryTree(self, root: Optional[TreeNode]) -> int:
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def diameter(node, res):
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if not node:
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return 0
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left = diameter(node.left, res)
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right = diameter(node.right, res)
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res[0] = max(res[0], left + right)
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return max(left, right) + 1
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res = [0]
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diameter(root, res)
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return res[0]
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