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solve problem Department Highest Salary

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`@@ -335,4 +335,5 @@ All solutions will be accepted!`
`335`	`335`	`\|626\|[Exchange Seats](https://leetcode-cn.com/problems/exchange-seats/description/)\|[mysql](./database/ExchangeSeats)\|Medium\|`
`336`	`336`	`\|178\|[Rank Scores](https://leetcode-cn.com/problems/rank-scores/description/)\|[mysql](./database/RankScore)\|Medium\|`
`337`	`337`	`\|180\|[Consecutive Numbers](https://leetcode-cn.com/problems/consecutive-numbers/description/)\|[mysql](./database/ConsecutiveNumbers)\|Medium\|`
`338`		`-\|177\|[Nth Highest Salary](https://leetcode-cn.com/problems/nth-highest-salary/description/)\|[mysql](./database/NthHighestSalary)\|Medium\|`
	`338`	`+\|177\|[Nth Highest Salary](https://leetcode-cn.com/problems/nth-highest-salary/description/)\|[mysql](./database/NthHighestSalary)\|Medium\|`
	`339`	`+\|184\|[Department Highest Salary](https://leetcode-cn.com/problems/department-highest-salary/description/)\|[mysql](./database/DepartmentHighestSalary)\|Medium\|`

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	`1`	`+# Department Highest Salary`
	`2`	`+We can solve this problem by MAX FUNCTION and sub-query`

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	`1`	`+# Write your MySQL query statement below`
	`2`	`+select d.Name as Department, e.Name as Employee, Salary`
	`3`	`+from Employee as e, Department as d`
	`4`	`+where e.DepartmentId = d.Id and Salary = (select max(Salary) from Employee where DepartmentId = d.Id)`

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