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# The algorithm uses a constant amount of extra space. It only uses a few pointer variables and does not require
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# any additional data structures that depend on the size of the input list.
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# Considerations:
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# Since a palindrome reads the same forward and backward, an intuitive way to solve this problem is to use two pointers—one placed at the beginning and
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# the other at the end. These pointers move toward the center, comparing the values at each step. While this approach is intuitive, it poses challenges
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# when working with singly linked lists. Singly linked lists only have the next pointers, so moving from the end toward the center requires additional steps.
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# To overcome this limitation, we solve this problem in three key steps: , , and If both halves of the list match, the linked list is a palindrome.
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# Here, reversing half the linked list allows us to use only the next pointers for comparison.
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# Approach:
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# 1. Use the two-pointer technique to find the middle of the linked list.
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# 2. Reverse the second half of the list.
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# 3. Compare the first half and the reversed second half to check for palindrome properties.
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# This approach efficiently determines if the list is a palindrome without using extra space for storing values.
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# This approach efficiently determines if the list is a palindrome without using extra space for storing values.
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