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<h2><a href="https://leetcode.com/problems/fruits-into-baskets-ii/?envType=daily-question&envId=2025年08月05日">3477. Fruits Into Baskets II</a></h2><h3>Easy</h3><hr><p>You are given two arrays of integers, <code>fruits</code> and <code>baskets</code>, each of length <code>n</code>, where <code>fruits[i]</code> represents the <strong>quantity</strong> of the <code>i<sup>th</sup></code> type of fruit, and <code>baskets[j]</code> represents the <strong>capacity</strong> of the <code>j<sup>th</sup></code> basket.</p>
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<p>From left to right, place the fruits according to these rules:</p>
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<ul>
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<li>Each fruit type must be placed in the <strong>leftmost available basket</strong> with a capacity <strong>greater than or equal</strong> to the quantity of that fruit type.</li>
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<li>Each basket can hold <b>only one</b> type of fruit.</li>
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<li>If a fruit type <b>cannot be placed</b> in any basket, it remains <b>unplaced</b>.</li>
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</ul>
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<p>Return the number of fruit types that remain unplaced after all possible allocations are made.</p>
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<p>&nbsp;</p>
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<p><strong class="example">Example 1:</strong></p>
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<div class="example-block">
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<p><strong>Input:</strong> <span class="example-io">fruits = [4,2,5], baskets = [3,5,4]</span></p>
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<p><strong>Output:</strong> <span class="example-io">1</span></p>
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<p><strong>Explanation:</strong></p>
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<ul>
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<li><code>fruits[0] = 4</code> is placed in <code>baskets[1] = 5</code>.</li>
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<li><code>fruits[1] = 2</code> is placed in <code>baskets[0] = 3</code>.</li>
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<li><code>fruits[2] = 5</code> cannot be placed in <code>baskets[2] = 4</code>.</li>
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</ul>
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<p>Since one fruit type remains unplaced, we return 1.</p>
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</div>
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<p><strong class="example">Example 2:</strong></p>
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<div class="example-block">
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<p><strong>Input:</strong> <span class="example-io">fruits = [3,6,1], baskets = [6,4,7]</span></p>
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<p><strong>Output:</strong> <span class="example-io">0</span></p>
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<p><strong>Explanation:</strong></p>
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<ul>
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<li><code>fruits[0] = 3</code> is placed in <code>baskets[0] = 6</code>.</li>
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<li><code>fruits[1] = 6</code> cannot be placed in <code>baskets[1] = 4</code> (insufficient capacity) but can be placed in the next available basket, <code>baskets[2] = 7</code>.</li>
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<li><code>fruits[2] = 1</code> is placed in <code>baskets[1] = 4</code>.</li>
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</ul>
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<p>Since all fruits are successfully placed, we return 0.</p>
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</div>
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<p>&nbsp;</p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li><code>n == fruits.length == baskets.length</code></li>
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<li><code>1 &lt;= n &lt;= 100</code></li>
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<li><code>1 &lt;= fruits[i], baskets[i] &lt;= 1000</code></li>
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</ul>

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