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更新剑指Offer58-II.左旋转字符串.md 格式修改

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Lines changed: 14 additions & 8 deletions

Original file line number	Diff line number	Diff line change
`@@ -125,17 +125,21 @@ python:`
`125`	`125`	`class Solution:`
`126`	`126`	`def reverseLeftWords(self, s: str, n: int) -> str:`
`127`	`127`	`return s[n:] + s[0:n]`
`128`		`-`
	`128`	+```
	`129`	+```python
`129`	`130`	`# 方法二:也可以使用上文描述的方法,有些面试中不允许使用切片,那就使用上文作者提到的方法`
`130`		`-# class Solution:`
`131`		`-# def reverseLeftWords(self, s: str, n: int) -> str:`
`132`		`-# s = list(s)`
`133`		`-# s[0:n] = list(reversed(s[0:n]))`
`134`		`-# s[n:] = list(reversed(s[n:]))`
`135`		`-# s.reverse()`
	`131`	`+class Solution:`
	`132`	`+ def reverseLeftWords(self, s: str, n: int) -> str:`
	`133`	`+ s = list(s)`
	`134`	`+ s[0:n] = list(reversed(s[0:n]))`
	`135`	`+ s[n:] = list(reversed(s[n:]))`
	`136`	`+ s.reverse()`
	`137`	`+`
	`138`	`+ return "".join(s)`
`136`	`139`
`137`		`-# return "".join(s)`
	`140`	+```
`138`	`141`
	`142`	+```python
`139`	`143`	`# 方法三:如果连reversed也不让使用,那么自己手写一个`
`140`	`144`	`class Solution:`
`141`	`145`	`def reverseLeftWords(self, s: str, n: int) -> str:`
`@@ -152,8 +156,10 @@ class Solution:`
`152`	`156`	`reverse_sub(res, 0, end)`
`153`	`157`	`return ''.join(res)`
`154`	`158`
	`159`	`+# 同方法二`
`155`	`160`	`# 时间复杂度:O(n)`
`156`	`161`	`# 空间复杂度:O(n),python的string为不可变,需要开辟同样大小的list空间来修改`
	`162`	`+`
`157`	`163`	```
`158`	`164`
`159`	`165`	```python 3

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