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binary number using the concept of dynamic memoric allocation

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Algorithms/Maths/Base Conversion/binary_number
- check_multple_of3.c
- readme.md

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	`1`	`+#include<stdio.h>`
	`2`	`+#include<conio.h>`
	`3`	`+#include<math.h>`
	`4`	`+`
	`5`	`+int checking(char*,int);`
	`6`	`+void main()`
	`7`	`+ {`
	`8`	`+ int b,i;`
	`9`	`+ char *a;`
	`10`	`+ a=(char*)calloc(b,sizeof(char));`
	`11`	`+ printf("\nhow many digit binary you want to enter\n");`
	`12`	`+ scanf("%d",&b);`
	`13`	`+`
	`14`	`+ printf("\nenter the binary number");`
	`15`	`+ fflush(stdin);`
	`16`	`+ gets(&a[0]);`
	`17`	`+ if(checking(a,b))`
	`18`	`+ {`
	`19`	`+ printf("\nthe given binary number after converting into decimal is a multiple of 3");`
	`20`	`+ }`
	`21`	`+ else`
	`22`	`+ printf("\nthe given binary number after converting into decimal is not a multiple of 3");`
	`23`	`+ getch();`
	`24`	`+ free(a);`
	`25`	`+ }`
	`26`	`+ int checking(char *a,int b)`
	`27`	`+ {`
	`28`	`+ int i,j=0,sum=0;`
	`29`	`+`
	`30`	`+ for(i=b-1;i>=0;i--)`
	`31`	`+ {`
	`32`	`+ sum=sum+pow(2,j)(int)(a+i);`
	`33`	`+ j++;`
	`34`	`+ }`
	`35`	`+ return(sum%3==0);`
	`36`	`+ }`

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	`1`	`+This program ask the user to enter the number of dits in a binary number and then wants the the user to enter that number and then checks whether the entered binary number is a multiple of 3 or not.`

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