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Commit 2815249

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quick sort
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‎src/main/java/grey/algorithm/code10_quicksort/Code_0010_LeetCode_0075_SortColors.java renamed to ‎src/main/java/grey/algorithm/code10_quicksort/Code_0001_LeetCode_0075_SortColors.java

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// 荷兰国旗问题
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// 仅0,1,2,所有的0放左边,所有的1放中间,所有的2放右边
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// https://leetcode.com/problems/sort-colors/
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public class Code_0010_LeetCode_0075_SortColors {
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public class Code_0001_LeetCode_0075_SortColors {
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public static void sortColors(int[] arr) {
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int l = -1; // 0 ~ l 是小于区域
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int r = arr.length; // l ~ r 是等于区域 , r ~ arr.length - 1 是大于区域

‎src/main/java/grey/algorithm/code10_quicksort/Code_0010_QuickSort.java renamed to ‎src/main/java/grey/algorithm/code10_quicksort/Code_0002_QuickSort.java

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// 4)那么所有情况都考虑,时间复杂度就是这种概率模型下的长期期望!
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// 时间复杂度O(N*logN),额外空间复杂度O(logN)都是这么来的。
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// 测评链接:https://www.lintcode.com/problem/464
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public class Code_0010_QuickSort {
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public class Code_0002_QuickSort {
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public static void sortIntegers2(int[] arr) {
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if (arr == null || arr.length <= 1) {
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return;

‎src/main/java/grey/algorithm/code10_quicksort/Code_0010_LeetCode_0215_KthLargestElementInAnArray.java renamed to ‎src/main/java/grey/algorithm/code10_quicksort/Code_0003_LeetCode_0215_KthLargestElementInAnArray.java

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* <p>
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* 方法2. bfprt算法 (严格收敛到O(N),但是空间复杂度O(N))
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*/
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public class Code_0010_LeetCode_0215_KthLargestElementInAnArray {
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public class Code_0003_LeetCode_0215_KthLargestElementInAnArray {
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public static void main(String[] args) {
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int[] arr = { -1, -1 };
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System.out.println(findKthLargest(arr, 2));

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