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更新 0746.使用最小花费爬楼梯.md Java代码

添加第一步支付费用版本的Java代码删除原版本中冗余的代码,已测试代码添加CPP代码的语法高亮

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Original file line number	Diff line number	Diff line change
`@@ -66,7 +66,7 @@`
`66`	`66`
`67`	`67`	`所以初始化代码为:`
`68`	`68`
`69`		-```
	`69`	+```CPP
`70`	`70`	`vector<int> dp(cost.size());`
`71`	`71`	`dp[0] = cost[0];`
`72`	`72`	`dp[1] = cost[1];`
`@@ -201,15 +201,32 @@ public:`
`201`	`201`
`202`	`202`
`203`	`203`	`### Java`
	`204`	`+`
`204`	`205`	```Java
	`206`	`+// 方式一:第一步支付费用`
`205`	`207`	`class Solution {`
`206`	`208`	`public int minCostClimbingStairs(int[] cost) {`
`207`		`- if (cost == null \|\| cost.length == 0) {`
`208`		`- return 0;`
`209`		`- }`
`210`		`- if (cost.length == 1) {`
`211`		`- return cost[0];`
	`209`	`+ int len = cost.length;`
	`210`	`+ int[] dp = new int[len + 1];`
	`211`	`+`
	`212`	`+ // 从下标为 0 或下标为 1 的台阶开始,因此支付费用为0`
	`213`	`+ dp[0] = 0;`
	`214`	`+ dp[1] = 0;`
	`215`	`+`
	`216`	`+ // 计算到达每一层台阶的最小费用`
	`217`	`+ for (int i = 2; i <= len; i++) {`
	`218`	`+ dp[i] = Math.min(dp[i - 1] + cost[i - 1], dp[i - 2] + cost[i - 2]);`
`212`	`219`	`}`
	`220`	`+`
	`221`	`+ return dp[len];`
	`222`	`+ }`
	`223`	`+}`
	`224`	+```
	`225`	`+`
	`226`	+```Java
	`227`	`+// 方式二:第一步不支付费用`
	`228`	`+class Solution {`
	`229`	`+ public int minCostClimbingStairs(int[] cost) {`
`213`	`230`	`int[] dp = new int[cost.length];`
`214`	`231`	`dp[0] = cost[0];`
`215`	`232`	`dp[1] = cost[1];`

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