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Merge pull request youngyangyang04#2711 from JasenWn/master

更新0503.下一个更大元素II的python版本

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problems
- 0503.下一个更大元素II.md

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`‎problems/0503.下一个更大元素II.md`

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Original file line number	Diff line number	Diff line change
`@@ -168,6 +168,7 @@ class Solution {`
`168`	`168`	```
`169`	`169`
`170`	`170`	`### Python:`
	`171`	`+> 版本一:`
`171`	`172`
`172`	`173`	```python
`173`	`174`	`class Solution:`
`@@ -181,6 +182,34 @@ class Solution:`
`181`	`182`	`stack.append(i%len(nums))`
`182`	`183`	`return dp`
`183`	`184`	```
	`185`	`+`
	`186`	`+> 版本二:针对版本一的优化`
	`187`	`+`
	`188`	+```python3
	`189`	`+class Solution:`
	`190`	`+ def nextGreaterElements(self, nums: List[int]) -> List[int]:`
	`191`	`+ res = [-1] * len(nums)`
	`192`	`+ stack = []`
	`193`	`+ #第一次遍历nums`
	`194`	`+ for i, num in enumerate(nums):`
	`195`	`+ while stack and num > nums[stack[-1]]:`
	`196`	`+ res[stack[-1]] = num`
	`197`	`+ stack.pop()`
	`198`	`+ stack.append(i)`
	`199`	`+ #此时stack仍有剩余,有部分数‘无下一个更大元素’待修正`
	`200`	`+ #第二次遍历nums`
	`201`	`+ for num in nums:`
	`202`	`+ #一旦stack为空,就表明所有数都有下一个更大元素,可以返回结果`
	`203`	`+ if not stack:`
	`204`	`+ return res`
	`205`	`+ while stack and num > nums[stack[-1]]:`
	`206`	`+ res[stack[-1]] = num`
	`207`	`+ stack.pop()`
	`208`	`+ #不要将已经有下一个更大元素的数加入栈,这样会重复赋值,只需对第一次遍历剩余的数再尝试寻找下一个更大元素即可`
	`209`	`+ #最后仍有部分最大数无法有下一个更大元素,返回结果`
	`210`	`+ return res`
	`211`	+```
	`212`	`+`
`184`	`213`	`### Go:`
`185`	`214`
`186`	`215`	```go
`@@ -203,7 +232,6 @@ func nextGreaterElements(nums []int) []int {`
`203`	`232`	`return result`
`204`	`233`	`}`
`205`	`234`	```
`206`		`-`
`207`	`235`	`### JavaScript:`
`208`	`236`
`209`	`237`	```JS

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