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Update 0093.复原IP地址.md

加入了python3,更类似于LeetCode131题代码的写法,看起来更简洁些

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`@@ -424,6 +424,30 @@ class Solution:`
`424`	`424`	`return True`
`425`	`425`	```
`426`	`426`
	`427`	`+python3; 简单拼接版本(类似Leetcode131写法):`
	`428`	+```python
	`429`	`+class Solution:`
	`430`	`+ def restoreIpAddresses(self, s: str) -> List[str]:`
	`431`	`+ global results, path`
	`432`	`+ results = []`
	`433`	`+ path = []`
	`434`	`+ self.backtracking(s,0)`
	`435`	`+ return results`
	`436`	`+`
	`437`	`+ def backtracking(self,s,index):`
	`438`	`+ global results,path`
	`439`	`+ if index == len(s) and len(path)==4:`
	`440`	`+ results.append('.'.join(path)) # 在连接时需要中间间隔符号的话就在''中间写上对应的间隔符`
	`441`	`+ return`
	`442`	`+ for i in range(index,len(s)):`
	`443`	`+ if len(path)>3: break # 剪枝`
	`444`	`+ temp = s[index:i+1]`
	`445`	`+ if (int(temp)<256 and int(temp)>0 and temp[0]!='0') or (temp=='0'):`
	`446`	`+ path.append(temp)`
	`447`	`+ self.backtracking(s,i+1)`
	`448`	`+ path.pop()`
	`449`	+```
	`450`	`+`
`427`	`451`	`## Go`
`428`	`452`
`429`	`453`	```go

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