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Commit 746e6af

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Merge pull request #59 from josemoracard/jose8-35-square-each-odd-number
exercises 35-square-each-odd-number to 41-frequency-of-words
2 parents b597f4f + b95c13d commit 746e6af

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# `35` Square odd numbers
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## 📝 Instrucciones:
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1. Escribe una función llamada `square_odd_numbers()` que acepte un string de números separados por comas como entrada, eleve al cuadrado solo los números impares y devuelva los resultados en una lista.
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## 📎 Ejemplo de entrada:
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```py
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square_odd_numbers("1,2,3,4,5,6,7,8,9")
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```
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## 📎 Ejemplo de salida:
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```py
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[1, 9, 25, 49, 81]
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```
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Use a list comprehension to square each odd number in a list. The list is input by a sequence of comma-separated numbers.
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Suppose the following input is supplied to the program:
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1,2,3,4,5,6,7,8,9
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Then, the output should be:
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1,3,5,7,9
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Hints:
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In case of input data being supplied to the question, it should be assumed to be a console input.
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# `35` Square odd numbers
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## 📝 Instructions:
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1. Write a function named `square_odd_numbers()` that accepts a string of comma-separated numbers as input, squares only the odd numbers, and returns the results as a list.
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## 📎 Example input:
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```py
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square_odd_numbers("1,2,3,4,5,6,7,8,9")
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```
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## 📎 Example output:
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```py
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[1, 9, 25, 49, 81]
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```
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# Your code here
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values = raw_input()
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numbers = [x for x in values.split(",") if int(x)%2!=0]
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print ",".join(numbers)
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# Your code here
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def square_odd_numbers(numbers_str):
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numbers_list = numbers_str.split(',')
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squared_odd_numbers = []
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for num_str in numbers_list:
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if num_str.isdigit():
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num = int(num_str)
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if num % 2 != 0:
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squared_odd_numbers.append(num**2)
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return squared_odd_numbers
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print(square_odd_numbers("1,2,3,4,5,6,7"))
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### SOLUTION 2 ### (List Comprehension)
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# def square_odd_numbers(numbers):
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# number_list = [int(num) for num in numbers.split(',')]
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# squared_odd_numbers = [num**2 for num in number_list if num % 2 != 0]
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# return squared_odd_numbers
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# print(square_odd_numbers("1,2,3,4,5,6,7"))

‎exercises/36-net-amount/README.es.md

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# `36` Net amount
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## 📝 Instrucciones:
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1. Escribe una función llamada `net_amount()` que calcule el saldo neto de una cuenta bancaria basándose en un registro de transacciones ingresado por parámetro. El formato del registro de transacciones se muestra a continuación:
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+ D 100
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+ W 200
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`D` significa depósito y `W` significa retiro.
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## 📎 Ejemplo de entrada:
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```py
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net_amount("D 300 D 300 W 200 D 100")
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```
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## 📎 Ejemplo de salida:
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```py
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500
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```

‎exercises/36-net-amount/README.md

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Write a program that computes the net amount of a bank account based a transaction log from console input. The transaction log format is shown as following:
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D 100
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W 200
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D means deposit while W means withdrawal.
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Suppose the following input is supplied to the program:
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D 300
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D 300
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W 200
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D 100
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Then, the output should be:
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500
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# `36` Net amount
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## 📝 Instructions:
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1. Write a function named `net_amount()` that computes the net amount of a bank account based on a transaction log from input. The transaction log format is shown as following:
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+ D 100
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+ W 200
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`D` means deposit while `W` means withdrawal.
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Hints:
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In case of input data being supplied to the question, it should be assumed to be a console input.
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## 📎 Example input:
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```py
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net_amount("D 300 D 300 W 200 D 100")
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```
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## 📎 Example output:
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```py
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500
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```

‎exercises/36-net-amount/app.py

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# Your code here
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# Your code here
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def net_amount(param):
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netAmount = 0
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total = 0
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values = param.split()
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for x in range(len(values)):
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if values[x] == 'D':
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netAmount+=int(values[x+1])
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total+=int(values[x+1])
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elif values[x] == 'W':
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netAmount-=int(values[x+1])
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return netAmount
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total-=int(values[x+1])
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return total
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print(net_amount("D 300 W 200 D 400"))

‎exercises/36-net-amount/test.py

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import pytest, io, sys, json, mock, re, os
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path = os.path.dirname(os.path.abspath(__file__))+'/app.py'
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@pytest.mark.it('The function net_amount must exist')
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def test_function_existence(capsys, app):
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assert app.net_amount
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@pytest.mark.it('The function net_amount must exist')
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def test_function_existence(capsys, app):
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assert app.net_amount
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@pytest.mark.it('The solution should work with other parameters. Testing with "W 300 D 300 W 200 D 300"')
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def test_output_negative(capsys, app):
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assert app.net_amount("W 300 D 300 W 200 W 300") == -500
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assert app.net_amount("W 300 D 300 W 200 W 300") == -500
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# `37` Validity of password
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## 📝 Instrucciones:
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Un sitio web requiere que los usuarios ingresen un nombre de usuario y una contraseña para registrarse. Escribe una función llamada `valid_password()` para verificar la validez de la contraseña ingresada por los usuarios. A continuación, se detallan los criterios para verificar la contraseña:
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1. Al menos 1 letra entre [a-z].
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2. Al menos 1 número entre [0-9].
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3. Al menos 1 letra entre [A-Z].
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4. Al menos 1 carácter de [$#@].
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5. Longitud mínima de la contraseña: 6.
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6. Longitud máxima de la contraseña: 12.
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Tu programa debe aceptar una contraseña y verificarla según los criterios anteriores. Si la contraseña es validada correctamente, la función devuelve el siguiente string `"Valid password"`, de lo contrario devuelve `"Invalid password. Please try again"`.
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## 📎 Ejemplo de entrada:
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```py
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valid_password("ABd1234@1")
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```
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## 📎 Ejemplo de salida:
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```py
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"Valid password"
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```
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## 💡 Pistas:
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+ Lee sobre expresiones regulares en Python.
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+ Necesitarás importar el módulo 're' (regular expressions) para poder usar la función `search()`.
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+ Para importarlo, copia y pega lo siguiente al inicio de tu archivo `import re`.

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