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doomsday.py

doomsday.py 1.53 KB

#!/bin/python3
# Doomsday algorithm info: https://en.wikipedia.org/wiki/Doomsday_rule

DOOMSDAY_LEAP = [4, 1, 7, 4, 2, 6, 4, 1, 5, 3, 7, 5]
DOOMSDAY_NOT_LEAP = [3, 7, 7, 4, 2, 6, 4, 1, 5, 3, 7, 5]
WEEK_DAY_NAMES = {
 0: "Sunday",
 1: "Monday",
 2: "Tuesday",
 3: "Wednesday",
 4: "Thursday",
 5: "Friday",
 6: "Saturday",
}

def get_week_day(year: int, month: int, day: int) -> str:
 """Returns the week-day name out of a given date.

>>> get_week_day(2020, 10, 24)
 'Saturday'
 >>> get_week_day(2017, 10, 24)
 'Tuesday'
 >>> get_week_day(2019, 5, 3)
 'Friday'
 >>> get_week_day(1970, 9, 16)
 'Wednesday'
 >>> get_week_day(1870, 8, 13)
 'Saturday'
 >>> get_week_day(2040, 3, 14)
 'Wednesday'

"""
 # minimal input check:
 assert len(str(year)) > 2, "year should be in YYYY format"
 assert 1 <= month <= 12, "month should be between 1 to 12"
 assert 1 <= day <= 31, "day should be between 1 to 31"

# Doomsday algorithm:
 century = year // 100
 century_anchor = (5 * (century % 4) + 2) % 7
 centurian = year % 100
 centurian_m = centurian % 12
 dooms_day = (
 (centurian // 12) + centurian_m + (centurian_m // 4) + century_anchor
 ) % 7
 day_anchor = (
 DOOMSDAY_NOT_LEAP[month - 1]
 if (year % 4 != 0) or (centurian == 0 and (year % 400) == 0)
 else DOOMSDAY_LEAP[month - 1]
 )
 week_day = (dooms_day + day - day_anchor) % 7
 return WEEK_DAY_NAMES[week_day]

if __name__ == "__main__":
 import doctest

doctest.testmod()

一键复制编辑原始数据按行查看历史

Ron U 提交于 2020年10月07日 20:22 +08:00 . Add doomsday algorithm (#2903)

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#!/bin/python3
# Doomsday algorithm info: https://en.wikipedia.org/wiki/Doomsday_rule

DOOMSDAY_LEAP = [4, 1, 7, 4, 2, 6, 4, 1, 5, 3, 7, 5]
DOOMSDAY_NOT_LEAP = [3, 7, 7, 4, 2, 6, 4, 1, 5, 3, 7, 5]
WEEK_DAY_NAMES = {
 0: "Sunday",
 1: "Monday",
 2: "Tuesday",
 3: "Wednesday",
 4: "Thursday",
 5: "Friday",
 6: "Saturday",
}


def get_week_day(year: int, month: int, day: int) -> str:
 """Returns the week-day name out of a given date.

 >>> get_week_day(2020, 10, 24)
 'Saturday'
 >>> get_week_day(2017, 10, 24)
 'Tuesday'
 >>> get_week_day(2019, 5, 3)
 'Friday'
 >>> get_week_day(1970, 9, 16)
 'Wednesday'
 >>> get_week_day(1870, 8, 13)
 'Saturday'
 >>> get_week_day(2040, 3, 14)
 'Wednesday'

 """
 # minimal input check:
 assert len(str(year)) > 2, "year should be in YYYY format"
 assert 1 <= month <= 12, "month should be between 1 to 12"
 assert 1 <= day <= 31, "day should be between 1 to 31"

 # Doomsday algorithm:
 century = year // 100
 century_anchor = (5 * (century % 4) + 2) % 7
 centurian = year % 100
 centurian_m = centurian % 12
 dooms_day = (
 (centurian // 12) + centurian_m + (centurian_m // 4) + century_anchor
 ) % 7
 day_anchor = (
 DOOMSDAY_NOT_LEAP[month - 1]
 if (year % 4 != 0) or (centurian == 0 and (year % 400) == 0)
 else DOOMSDAY_LEAP[month - 1]
 )
 week_day = (dooms_day + day - day_anchor) % 7
 return WEEK_DAY_NAMES[week_day]


if __name__ == "__main__":
 import doctest

 doctest.testmod()