public class ExMath {public static boolean isPrime(int x) {if (x == 1) return false;if (x == 2 || x == 3) return true;if (x % 2 == 0) return false;for (int i = 3; i <= Math.sqrt(x + 1); i += 2) {if (x % i == 0) return false;}return true;}//动态规划求斐波那契数//T=O(N)public static long fibonacci_dp(int n) {//f(0)=f(1)=1if (n <= 1) return 1;long last = 1, nextToLast = 1, answer = 1;for (int i = 2; i <= n; i++) {answer = last + nextToLast;nextToLast = last;last = answer;}return answer;}public static long dec2Bi(int x) {int remainder = x;long ret = 0;int level = 0;while (remainder != 0) {ret += (long) remainder % 2 * Math.pow(10, level++);remainder /= 2;}return ret;}public static int min(int a, int b, int c) {int ret = a;if (ret > b) ret = b;if (ret > c) ret = c;return ret;}//求两个正整数的最大公因数public static int gcd(int a, int b) {if (a < b) {int tmp = a;a = b;b = tmp;}int remainder = a % b;while (remainder != 0) {a = b;b = remainder;remainder = a % b;}return b;}//求三个正整数的最大公因数public static int gcd(int a, int b, int c) {//求多个数的最大公因数:多次辗转相除法//先求a,b的最大公因数gcd(a,b),再求gcd(a,b)与c的最大公因数int tmp = gcd(a, b);return gcd(tmp, c);}public static long fibonacci(int n) {if (n == 1 || n == 2) return 1;else return fibonacci(n - 1) + fibonacci(n - 2);}public static long fact(int n) {if (n < 0) return 0;if (n == 0 || n == 1) return 1;else return n * fact(n - 1);}}
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