dynamic_programming/fizz_buzz.py · elihe/Python

代码拉取完成,页面将自动刷新

扫描微信二维码支付

取消

支付完成

richgiteeai

Watch

不关注关注所有动态仅关注版本发行动态关注但不提醒动态

1 Star 0 Fork 324

elihe/Python

forked from 编程语言算法集/Python

代码 Issues 0 Pull Requests 0 Wiki 统计流水线

服务

加入 Gitee

与超过 1400万开发者一起发现、参与优秀开源项目,私有仓库也完全免费 :)

免费加入

已有帐号? 立即登录

文件

master

分支 (86)

管理

master

Fewer-forward-propogations-to-speed-tests

cclauss-patch-1

Add-dataclasses-to-binary_search_tree.py

Simplify-is_bst.py

test-cov-gh-action

dhruv/remove

Remove-backslashes-from-is_palindrome.py

fuzzy_operations.py-on-Python-3.12

Python-3.12-on-Debian-bookworm

fix-maclaurin_series-on-Python3.12

pre-commit-ci-update-config

Py3.12

fix-ruff

pipx-install-pre-commit-ruff

ruff-rule-ISC001

Re-enable-tests

Rename-is_palindrome.py-to-is_int_palindrome.py

Add-more-ruff-rules

ruff

克隆/下载

HTTPS SSH SVN SVN+SSH 下载ZIP

提示

下载代码请复制以下命令到终端执行

为确保你提交的代码身份被 Gitee 正确识别,请执行以下命令完成配置

git config --global user.name userName 
git config --global user.email userEmail

初次使用 SSH 协议进行代码克隆、推送等操作时,需按下述提示完成 SSH 配置

1 生成 RSA 密钥

2 获取 RSA 公钥内容,并配置到 SSH公钥中

在 Gitee 上使用 SVN,请访问使用指南

使用 HTTPS 协议时,命令行会出现如下账号密码验证步骤。基于安全考虑,Gitee 建议配置并使用私人令牌替代登录密码进行克隆、推送等操作

Username for 'https://gitee.com': userName

Password for 'https://userName@gitee.com': # 私人令牌

分支 86

标签 0

Python

dynamic_programming

fizz_buzz.py

fizz_buzz.py 1.90 KB

# https://en.wikipedia.org/wiki/Fizz_buzz#Programming

def fizz_buzz(number: int, iterations: int) -> str:
 """
 Plays FizzBuzz.
 Prints Fizz if number is a multiple of 3.
 Prints Buzz if its a multiple of 5.
 Prints FizzBuzz if its a multiple of both 3 and 5 or 15.
 Else Prints The Number Itself.
 >>> fizz_buzz(1,7)
 '1 2 Fizz 4 Buzz Fizz 7 '
 >>> fizz_buzz(1,0)
 Traceback (most recent call last):
 ...
 ValueError: Iterations must be done more than 0 times to play FizzBuzz
 >>> fizz_buzz(-5,5)
 Traceback (most recent call last):
 ...
 ValueError: starting number must be
 and integer and be more than 0
 >>> fizz_buzz(10,-5)
 Traceback (most recent call last):
 ...
 ValueError: Iterations must be done more than 0 times to play FizzBuzz
 >>> fizz_buzz(1.5,5)
 Traceback (most recent call last):
 ...
 ValueError: starting number must be
 and integer and be more than 0
 >>> fizz_buzz(1,5.5)
 Traceback (most recent call last):
 ...
 ValueError: iterations must be defined as integers
 """
 if not isinstance(iterations, int):
 raise ValueError("iterations must be defined as integers")
 if not isinstance(number, int) or not number >= 1:
 raise ValueError(
 """starting number must be
 and integer and be more than 0"""
 )
 if not iterations >= 1:
 raise ValueError("Iterations must be done more than 0 times to play FizzBuzz")

out = ""
 while number <= iterations:
 if number % 3 == 0:
 out += "Fizz"
 if number % 5 == 0:
 out += "Buzz"
 if 0 not in (number % 3, number % 5):
 out += str(number)

# print(out)
 number += 1
 out += " "
 return out

if __name__ == "__main__":
 import doctest

doctest.testmod()

一键复制编辑原始数据按行查看历史

Christian Clauss 提交于 2023年03月02日 00:23 +08:00 . Make some ruff fixes (#8154)

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64

# https://en.wikipedia.org/wiki/Fizz_buzz#Programming


def fizz_buzz(number: int, iterations: int) -> str:
 """
 Plays FizzBuzz.
 Prints Fizz if number is a multiple of 3.
 Prints Buzz if its a multiple of 5.
 Prints FizzBuzz if its a multiple of both 3 and 5 or 15.
 Else Prints The Number Itself.
 >>> fizz_buzz(1,7)
 '1 2 Fizz 4 Buzz Fizz 7 '
 >>> fizz_buzz(1,0)
 Traceback (most recent call last):
 ...
 ValueError: Iterations must be done more than 0 times to play FizzBuzz
 >>> fizz_buzz(-5,5)
 Traceback (most recent call last):
 ...
 ValueError: starting number must be
 and integer and be more than 0
 >>> fizz_buzz(10,-5)
 Traceback (most recent call last):
 ...
 ValueError: Iterations must be done more than 0 times to play FizzBuzz
 >>> fizz_buzz(1.5,5)
 Traceback (most recent call last):
 ...
 ValueError: starting number must be
 and integer and be more than 0
 >>> fizz_buzz(1,5.5)
 Traceback (most recent call last):
 ...
 ValueError: iterations must be defined as integers
 """
 if not isinstance(iterations, int):
 raise ValueError("iterations must be defined as integers")
 if not isinstance(number, int) or not number >= 1:
 raise ValueError(
 """starting number must be
 and integer and be more than 0"""
 )
 if not iterations >= 1:
 raise ValueError("Iterations must be done more than 0 times to play FizzBuzz")

 out = ""
 while number <= iterations:
 if number % 3 == 0:
 out += "Fizz"
 if number % 5 == 0:
 out += "Buzz"
 if 0 not in (number % 3, number % 5):
 out += str(number)

 # print(out)
 number += 1
 out += " "
 return out


if __name__ == "__main__":
 import doctest

 doctest.testmod()